For z₁ = 7 − j7 and z₂ = 2 − j5, find the real part of w = −2z₁ − 3z̄₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 7 − j7z₂ = 2 − j5
Re(w) =
2.Easy
For z₁ = 5 + j5 and z₂ = −5 − j2, find the imaginary part of the product z₁·z₂.
z₁ = 5 + j5z₂ = −5 − j2
Im(z₁z₂) =
3.Medium
Find the argument θ of z = −3 + j6 in degrees, as the principal value between −180° and 180°.
z = −3 + j6
θ = °
4.Medium
The number z = 4·ej1.2 has its angle in radians. Find its real part a.
r = 4θ = 1.2 rad
a =
5.Hard
Solve z² + 2z + 26 = 0. The roots are a ± jb; find b > 0.
p = 2q = 26
b =
6.Hard
One root of z³ − 4z² + 21z − 34 = 0 is z₁ = 1 + j4. The coefficients are real. Find the real root r.
z₁ = 1 + j4
r =
Answer key
- 1. Re(w) = −20
- 2. Im(z₁z₂) = −35
- 3. θ = 116.6 °
- 4. a = 1.449
- 5. b = 5
- 6. r = 2
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