The Argand diagram shows z₁ = 3 − j2 and z₂ = −5 − j. Click the point that represents z₁ + z₂.
- 1A (−2 + j3)
- 2B (−3 − j2)
- 3C (8 − j)
- 4D (−2 − j3)
The Argand diagram shows z₁ = 3 − j2 and z₂ = −5 − j. Click the point that represents z₁ + z₂.
For z₁ = −4 − j6 and z₂ = −2 − j6, find the imaginary part of w = 3z₁ + 2z₂.
Write z = 4∠140° in rectangular form a + jb and give the real part a.
The diagram shows z = −1 − j3. With w = 0.5∠−90°, click the point that represents z/w.
Use De Moivre's theorem to find the imaginary part of z³ for z = −1 + j.
The roots of zⁿ = w with n = 6 and w = 729∠135° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, …, 5. Find the imaginary part of z₀.
Full step-by-step solutions: practise this topic on examproblems.com.