For z₁ = −7 − j5 and z₂ = −2 − j6, find the imaginary part of w = −z₁ + 5z̄₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −7 − j5z₂ = −2 − j6
Im(w) =
2.Easy
For z₁ = −5 + j and z₂ = −2 + j, find the modulus of the product, |z₁z₂|.
z₁ = −5 + jz₂ = −2 + j
|z₁z₂| =
3.Medium
Find the argument θ of z = −9 + j3 in degrees, as the principal value between −180° and 180°.
z = −9 + j3
θ = °
4.Medium
Given z₁ = 2∠70° and z₂ = 3∠−95°, find the imaginary part of w = z₁·z₂.
z₁ = 2∠70°z₂ = 3∠−95°
Im(w) =
5.Hard
The roots of zⁿ = w with n = 3 and w = 27∠60° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2. Find the real part of z₁.
w = 27∠60°n = 3k = 1
Re(z₁) =
6.Hard
The roots of zⁿ = w with n = 3 and w = 27∠180° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2. Find the imaginary part of z₂.
w = 27∠180°n = 3k = 2
Im(z₂) =
Answer key
- 1. Im(w) = 35
- 2. |z₁z₂| = 11.4
- 3. θ = 161.6 °
- 4. Im(w) = −2.536
- 5. Re(z₁) = −2.298
- 6. Im(z₂) = −2.598
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