For z₁ = 3 − j and z₂ = −6 − j3, find the modulus of the product, |z₁z₂|.
Complex numbers worksheet with answers
1.Easy
z₁ = 3 − jz₂ = −6 − j3
|z₁z₂| =
2.Easy
For z₁ = −6 − j8 and z₂ = −1 − j, find the real part of w = −2z₁ − 2z̄₂.
z₁ = −6 − j8z₂ = −1 − j
Re(w) =
3.Medium
Write z = 10∠125° in rectangular form a + jb and give the real part a.
r = 10θ = 125°
a =
4.Medium
The diagram shows z = 4 − j3. With w = 2∠−90°, click the point that represents z·w.
z = 4 − j3w = 2∠−90°
- 1A (−6 − j8)
- 2B (8 − j6)
- 3C (6 + j8)
- 4D (−3 − j4)
5.Hard
Exactly one of the points A–D is a root of z³ = 27∠−90°. Click it.
w = 27∠−90°n = 3
- 1A (3∠0°)
- 2B (3∠30°)
- 3C (3∠−30°)
- 4D (5.4∠−30°)
6.Hard
Find the imaginary part of (1 + j2)⁴.
z = 1 + j2n = 4
Im(z⁴) =
Answer key
- 1. |z₁z₂| = 21.21
- 2. Re(w) = 14
- 3. a = −5.736
- 4. A (−6 − j8)
- 5. C (3∠−30°)
- 6. Im(z⁴) = −24
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