For z₁ = −4 − j and z₂ = 1 − j5, find the modulus of the product, |z₁z₂|.
Complex numbers worksheet with answers
1.Easy
z₁ = −4 − jz₂ = 1 − j5
|z₁z₂| =
2.Easy
For z₁ = −7 + j7 and z₂ = −5 + j2, find the imaginary part of the product z₁·z₂.
z₁ = −7 + j7z₂ = −5 + j2
Im(z₁z₂) =
3.Medium
The diagram shows z = −2 − j. With w = 0.5∠−90°, click the point that represents z/w.
z = −2 − jw = 0.5∠−90°
- 1A (2 − j4)
- 2B (1 − j2)
- 3C (−2 + j4)
- 4D (−4 − j2)
4.Medium
Given z₁ = 2∠125° and z₂ = 0.5∠−25°, find the imaginary part of w = z₁·z₂.
z₁ = 2∠125°z₂ = 0.5∠−25°
Im(w) =
5.Hard
Exactly one of the points A–D is a root of z⁶ = 64∠−90°. Click it.
w = 64∠−90°n = 6
- 1A (3.6∠15°)
- 2B (2∠−90°)
- 3C (2∠−15°)
- 4D (2∠15°)
6.Hard
Solve z² − 4z + 6.25 = 0. The roots are a ± jb; find the real part a.
p = −4q = 6.25
a =
Answer key
- 1. |z₁z₂| = 21.02
- 2. Im(z₁z₂) = −49
- 3. A (2 − j4)
- 4. Im(w) = 0.9848
- 5. C (2∠−15°)
- 6. a = 2
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