For z₁ = 4 + j6 and z₂ = 6 − j5, find the real part of w = 2z₁ − 3z̄₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 4 + j6z₂ = 6 − j5
Re(w) =
2.Easy
For z₁ = −6 − j and z₂ = −4 − j5, find the real part of the quotient z₁/z₂.
z₁ = −6 − jz₂ = −4 − j5
Re(z₁/z₂) =
3.Medium
Given z₁ = 5∠100° and z₂ = 4∠110°, find the argument θ of w = z₁/z₂ in degrees, between −180° and 180°.
z₁ = 5∠100°z₂ = 4∠110°
θ = °
4.Medium
Write z = 7 + j5 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = 7 + j5
θ = rad
5.Hard
Use De Moivre's theorem to find the real part of z⁴ for z = −√3 + j.
z = −√3 + jn = 4
Re(z⁴) =
6.Hard
The roots of zⁿ = w with n = 5 and w = 32∠135° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, …, 4. Find the imaginary part of z₀.
w = 32∠135°n = 5k = 0
Im(z₀) =
Answer key
- 1. Re(w) = −10
- 2. Re(z₁/z₂) = 0.7073
- 3. θ = −10 °
- 4. θ = 0.6202 rad
- 5. Re(z⁴) = −8
- 6. Im(z₀) = 0.908
Full step-by-step solutions: practise this topic on examproblems.com.