For z₁ = 6 − j7 and z₂ = 1 − j4, find the imaginary part of w = 2z₁ − 3z̄₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 6 − j7z₂ = 1 − j4
Im(w) =
2.Easy
For z₁ = 4 − j5 and z₂ = −1 − j4, find the imaginary part of the product z₁·z₂.
z₁ = 4 − j5z₂ = −1 − j4
Im(z₁z₂) =
3.Medium
Find the argument θ of z = −5 − j4 in degrees, as the principal value between −180° and 180°.
z = −5 − j4
θ = °
4.Medium
Write z = −7 − j7 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = −7 − j7
θ = rad
5.Hard
The roots of zⁿ = w with n = 4 and w = 81∠120° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2, 3. Find the imaginary part of z₂.
w = 81∠120°n = 4k = 2
Im(z₂) =
6.Hard
Find the real part of (−3 − j2)⁵.
z = −3 − j2n = 5
Re(z⁵) =
Answer key
- 1. Im(w) = −26
- 2. Im(z₁z₂) = −11
- 3. θ = −141.3 °
- 4. θ = −2.356 rad
- 5. Im(z₂) = −1.5
- 6. Re(z⁵) = 597
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