For z₁ = 1 − j7 and z₂ = 4 + j4, find the imaginary part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 1 − j7z₂ = 4 + j4
Im(z₁z₂) =
2.Easy
For z₁ = 1 + j7 and z₂ = 4 − j4, find the imaginary part of the quotient z₁/z₂.
z₁ = 1 + j7z₂ = 4 − j4
Im(z₁/z₂) =
3.Medium
Write z = 6 − j8 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = 6 − j8
θ = rad
4.Medium
The diagram shows z = −4 + j3. With w = 0.5∠90°, click the point that represents z/w.
z = −4 + j3w = 0.5∠90°
- 1A (−6 − j8)
- 2B (−8 + j6)
- 3C (3 + j4)
- 4D (6 + j8)
5.Hard
One root of z³ − 7z² + 17z + 25 = 0 is z₁ = 4 + j3. The coefficients are real. Find the real root r.
z₁ = 4 + j3
r =
6.Hard
Use De Moivre's theorem to find the real part of z⁶ for z = √3 + j.
z = √3 + jn = 6
Re(z⁶) =
Answer key
- 1. Im(z₁z₂) = −24
- 2. Im(z₁/z₂) = 1
- 3. θ = −0.9273 rad
- 4. D (6 + j8)
- 5. r = −1
- 6. Re(z⁶) = −64
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