For z₁ = 6 + j2 and z₂ = −3 + j5, find the modulus of the product, |z₁z₂|.
Complex numbers worksheet with answers
1.Easy
z₁ = 6 + j2z₂ = −3 + j5
|z₁z₂| =
2.Easy
For z₁ = −3 + j5 and z₂ = 2 + j, find the real part of the product z₁·z₂.
z₁ = −3 + j5z₂ = 2 + j
Re(z₁z₂) =
3.Medium
Write z = −9 + j8 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = −9 + j8
θ = rad
4.Medium
Find the argument θ of z = −9 + j5 in degrees, as the principal value between −180° and 180°.
z = −9 + j5
θ = °
5.Hard
Solve z² + 5z + 22.25 = 0. The roots are a ± jb; find b > 0.
p = 5q = 22.25
b =
6.Hard
One root of z³ − 5z² + 8z − 6 = 0 is z₁ = 1 + j. The coefficients are real. Find the real root r.
z₁ = 1 + j
r =
Answer key
- 1. |z₁z₂| = 36.88
- 2. Re(z₁z₂) = −11
- 3. θ = 2.415 rad
- 4. θ = 150.9 °
- 5. b = 4
- 6. r = 3
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