For z₁ = −5 − j4 and z₂ = −3 − j, find the imaginary part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −5 − j4z₂ = −3 − j
Im(z₁z₂) =
2.Easy
The Argand diagram shows z₁ = 3 + j. Click the point that represents z̄₁.
z₁ = 3 + j
- 1A (1 + j3)
- 2B (3 − j)
- 3C (−3 − j)
- 4D (−1 − j3)
3.Medium
Write z = −6 − j4 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = −6 − j4
θ = rad
4.Medium
Find the argument θ of z = −9 + j6 in degrees, as the principal value between −180° and 180°.
z = −9 + j6
θ = °
5.Hard
The roots of zⁿ = w with n = 4 and w = 81∠90° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2, 3. Find the imaginary part of z₃.
w = 81∠90°n = 4k = 3
Im(z₃) =
6.Hard
One root of z³ − 2z² − 11z + 52 = 0 is z₁ = 3 + j2. The coefficients are real. Find the real root r.
z₁ = 3 + j2
r =
Answer key
- 1. Im(z₁z₂) = 17
- 2. B (3 − j)
- 3. θ = −2.554 rad
- 4. θ = 146.3 °
- 5. Im(z₃) = −2.772
- 6. r = −4
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