For z₁ = 3 + j6 and z₂ = 1 − j, find the real part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 3 + j6z₂ = 1 − j
Re(z₁z₂) =
2.Easy
For z₁ = −8 + j2 and z₂ = −1 + j4, find the real part of w = 4z₁ − 2z̄₂.
z₁ = −8 + j2z₂ = −1 + j4
Re(w) =
3.Medium
Write z = 12∠125° in rectangular form a + jb and give the real part a.
r = 12θ = 125°
a =
4.Medium
Find the argument θ of z = −1 + j9 in degrees, as the principal value between −180° and 180°.
z = −1 + j9
θ = °
5.Hard
Exactly one of the points A–D is a root of z⁶ = 64∠90°. Click it.
w = 64∠90°n = 6
- 1A (2∠90°)
- 2B (2∠45°)
- 3C (3.6∠−15°)
- 4D (2∠−45°)
6.Hard
Use De Moivre's theorem to find the imaginary part of z⁷ for z = −√3 + j.
z = −√3 + jn = 7
Im(z⁷) =
Answer key
- 1. Re(z₁z₂) = 9
- 2. Re(w) = −30
- 3. a = −6.883
- 4. θ = 96.34 °
- 5. D (2∠−45°)
- 6. Im(z⁷) = −64
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