Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 145 kPasandγ = 17.5 kN/m³5 mclayγsat​ = 17.5 kN/m³Cc​ = 0.35, e0​ = 1.058 mwater tableX

An 8 m thick normally consolidated clay layer (γsat = 17.5 kN/m³, Cc = 0.35, e₀ = 1.05) lies below 5 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 145 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 5 m, γ = 17.5 kN/m³clay: H = 8 m, γsat = 17.5 kN/m³γw = 9.81 kN/m³Cc = 0.35e0 = 1.05Δσ = 145 kPa
S = mm
2.Easy
Δσ = 70 kPasandclayCc​ = 0.25e0​ = 0.65σ′0​ = 115 kPa6 mwater table

A 6 m thick layer of normally consolidated clay (Cc = 0.25, e₀ = 0.65) has an effective vertical stress of 115 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 70 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 6 mCc = 0.25e0 = 0.65σ′0 = 115 kPaΔσ = 70 kPa
S = mm
3.Medium
Δσ = 150 kPasandclayCc​ = 0.35, Cr​ = 0.04e0​ = 1.15σ′0​ = 60 kPaσ′p​ = 160 kPa8 mwater table

An 8 m thick overconsolidated clay layer has Cc = 0.35, Cr = 0.04 and e₀ = 1.15. At its mid-depth the effective vertical stress is 60 kPa and the preconsolidation pressure is 160 kPa. A new building adds 150 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 8 mCc = 0.35Cr = 0.04e0 = 1.15σ′0 = 60 kPaσ′p = 160 kPaΔσ = 150 kPa
S = mm
4.Medium
Δσ = 110 kPasandclayCc​ = 0.45, Cr​ = 0.04e0​ = 0.7σ′0​ = 55 kPaOCR = 2.53.5 mwater table

A 3.5 m thick overconsolidated clay layer has Cc = 0.45, Cr = 0.04 and e₀ = 0.7. At its mid-depth the effective vertical stress is 55 kPa and the overconsolidation ratio is OCR = 2.5. A new building adds 110 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3.5 mCc = 0.45Cr = 0.04e0 = 0.7σ′0 = 55 kPaOCR = 2.5Δσ = 110 kPa
S = mm
5.Hard
sandclayH = 3 mcv​ = 2.5 m²/year3 msandwater table

A clay layer 3 m thick has a coefficient of consolidation cv = 2.5 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 50% average consolidation the time factor is Tv = 0.197. How many years t does the layer take to reach 50% consolidation?

H = 3 mcv = 2.5 m²/yearU = 50%Tv = 0.197double drainage
t = years
6.Hard
sandclayH = 10 m10 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 25 mm thick, drained at the top and bottom, reaches 50% consolidation in 10 min. In the field the same clay forms a layer 10 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 25 mmtlab = 10 minH = 10 mfield: single drainage
t = days

Answer key

  1. 1. S = 474.7 mm
  2. 2. S = 187.7 mm
  3. 3. S = 217.2 mm
  4. 4. S = 106.1 mm
  5. 5. t = 0.1773 years
  6. 6. t = 4444 days

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