Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 140 kPasandclayCc​ = 0.5e0​ = 1.05σ′0​ = 130 kPa8 mwater table

An 8 m thick layer of normally consolidated clay (Cc = 0.5, e₀ = 1.05) has an effective vertical stress of 130 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 140 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 8 mCc = 0.5e0 = 1.05σ′0 = 130 kPaΔσ = 140 kPa
S = mm
2.Easy
Δσ = 80 kPasandγ = 18 kN/m³2 mclayγsat​ = 19.5 kN/m³Cc​ = 0.6, e0​ = 0.68 mwater tableX

An 8 m thick normally consolidated clay layer (γsat = 19.5 kN/m³, Cc = 0.6, e₀ = 0.6) lies below 2 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 80 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 2 m, γ = 18 kN/m³clay: H = 8 m, γsat = 19.5 kN/m³γw = 9.81 kN/m³Cc = 0.6e0 = 0.6Δσ = 80 kPa
S = mm
3.Medium
Δσ = 40 kPasandclayCc​ = 0.3, Cr​ = 0.05e0​ = 0.7σ′0​ = 45 kPaOCR = 1.57 mwater table

A 7 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.05 and e₀ = 0.7. At its mid-depth the effective vertical stress is 45 kPa and the overconsolidation ratio is OCR = 1.5. A new building adds 40 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 7 mCc = 0.3Cr = 0.05e0 = 0.7σ′0 = 45 kPaOCR = 1.5Δσ = 40 kPa
S = mm
4.Medium
Δσ = 160 kPasandclayCc​ = 0.25, Cr​ = 0.05e0​ = 1.2σ′0​ = 90 kPaσ′p​ = 180 kPa6.5 mwater table

A 6.5 m thick overconsolidated clay layer has Cc = 0.25, Cr = 0.05 and e₀ = 1.2. At its mid-depth the effective vertical stress is 90 kPa and the preconsolidation pressure is 180 kPa. A new building adds 160 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 6.5 mCc = 0.25Cr = 0.05e0 = 1.2σ′0 = 90 kPaσ′p = 180 kPaΔσ = 160 kPa
S = mm
5.Hard
sandclayH = 8 mcv​ = 3 m²/year8 msandwater table

A clay layer 8 m thick has a coefficient of consolidation cv = 3 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 60% average consolidation the time factor is Tv = 0.287. How many years t does the layer take to reach 60% consolidation?

H = 8 mcv = 3 m²/yearU = 60%Tv = 0.287double drainage
t = years
6.Hard
sandclayH = 6.5 mcv​ = 3 m²/year6.5 mimpervious rockwater table

A clay layer 6.5 m thick has a coefficient of consolidation cv = 3 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 6.5 mcv = 3 m²/yearU = 80%Tv = 0.567single drainage
t = years

Answer key

  1. 1. S = 619.4 mm
  2. 2. S = 948 mm
  3. 3. S = 159.9 mm
  4. 4. S = 149.8 mm
  5. 5. t = 1.531 years
  6. 6. t = 7.985 years

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