Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
Δσ = 120 kPasandγ = 17.5 kN/m³2.5 mclayγsat​ = 19 kN/m³Cc​ = 0.45, e0​ = 0.855 mwater tableX

A 5 m thick normally consolidated clay layer (γsat = 19 kN/m³, Cc = 0.45, e₀ = 0.85) lies below 2.5 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 120 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 2.5 m, γ = 17.5 kN/m³clay: H = 5 m, γsat = 19 kN/m³γw = 9.81 kN/m³Cc = 0.45e0 = 0.85Δσ = 120 kPa
S = mm
2.Easy
Δσ = 45 kPasandγ = 18.5 kN/m³5.5 mclayγsat​ = 18 kN/m³Cc​ = 0.35, e0​ = 0.67 mwater tableX

A 7 m thick normally consolidated clay layer (γsat = 18 kN/m³, Cc = 0.35, e₀ = 0.6) lies below 5.5 m of sand (γ = 18.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 45 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 5.5 m, γ = 18.5 kN/m³clay: H = 7 m, γsat = 18 kN/m³γw = 9.81 kN/m³Cc = 0.35e0 = 0.6Δσ = 45 kPa
S = mm
3.Medium
Δσ = 35 kPasandclayCc​ = 0.35, Cr​ = 0.02e0​ = 1.2σ′0​ = 60 kPaσ′p​ = 180 kPa6 mwater table

A 6 m thick overconsolidated clay layer has Cc = 0.35, Cr = 0.02 and e₀ = 1.2. At its mid-depth the effective vertical stress is 60 kPa and the preconsolidation pressure is 180 kPa. A new building adds 35 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 6 mCc = 0.35Cr = 0.02e0 = 1.2σ′0 = 60 kPaσ′p = 180 kPaΔσ = 35 kPa
S = mm
4.Medium
Δσ = 180 kPasandclayCc​ = 0.5, Cr​ = 0.05e0​ = 1.2σ′0​ = 55 kPaOCR = 38 mwater table

An 8 m thick overconsolidated clay layer has Cc = 0.5, Cr = 0.05 and e₀ = 1.2. At its mid-depth the effective vertical stress is 55 kPa and the overconsolidation ratio is OCR = 3. A new building adds 180 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 8 mCc = 0.5Cr = 0.05e0 = 1.2σ′0 = 55 kPaOCR = 3Δσ = 180 kPa
S = mm
5.Hard
sandclayH = 6 m6 msandwater table

In a laboratory oedometer test, a clay specimen 19 mm thick, drained at the top and bottom, reaches 50% consolidation in 10 min. In the field the same clay forms a layer 6 m thick. It lies between two sand layers, so water drains out at the top and the bottom. How many days t does the field layer take to reach 50% consolidation?

hlab = 19 mmtlab = 10 minH = 6 mfield: double drainage
t = days
6.Hard
sandclayH = 9 mcv​ = 3 m²/year9 mimpervious rockwater table

A clay layer 9 m thick has a coefficient of consolidation cv = 3 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 70% average consolidation the time factor is Tv = 0.403. How many years t does the layer take to reach 70% consolidation?

H = 9 mcv = 3 m²/yearU = 70%Tv = 0.403single drainage
t = years

Answer key

  1. 1. S = 543.5 mm
  2. 2. S = 197.1 mm
  3. 3. S = 10.89 mm
  4. 4. S = 366 mm
  5. 5. t = 692.5 days
  6. 6. t = 10.88 years

Full step-by-step solutions: practise this topic on examproblems.com.