A 4 m thick normally consolidated clay layer (γsat = 18 kN/m³, Cc = 0.25, e₀ = 1.2) lies below 3 m of sand (γ = 19 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 80 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
Consolidation settlement worksheet with answers
A 4 m thick normally consolidated clay layer (γsat = 17.5 kN/m³, Cc = 0.4, e₀ = 0.9) lies below 5.5 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 45 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
A 6 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.06 and e₀ = 0.6. At its mid-depth the effective vertical stress is 110 kPa and the preconsolidation pressure is 210 kPa. A new building adds 95 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A 7.5 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.05 and e₀ = 1.15. At its mid-depth the effective vertical stress is 120 kPa and the overconsolidation ratio is OCR = 2. A new building adds 70 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A clay layer 9.5 m thick has a coefficient of consolidation cv = 1.5 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 90% average consolidation the time factor is Tv = 0.848. How many years t does the layer take to reach 90% consolidation?
A clay layer 3.5 m thick has a coefficient of consolidation cv = 5 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?
Answer key
- 1. S = 145.5 mm
- 2. S = 121.3 mm
- 3. S = 60.83 mm
- 4. S = 34.81 mm
- 5. t = 12.76 years
- 6. t = 0.3473 years
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