Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 85 kPasandγ = 17.5 kN/m³6 mclayγsat​ = 19.5 kN/m³Cc​ = 0.45, e0​ = 0.854 mwater tableX

A 4 m thick normally consolidated clay layer (γsat = 19.5 kN/m³, Cc = 0.45, e₀ = 0.85) lies below 6 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 85 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 6 m, γ = 17.5 kN/m³clay: H = 4 m, γsat = 19.5 kN/m³γw = 9.81 kN/m³Cc = 0.45e0 = 0.85Δσ = 85 kPa
S = mm
2.Easy
Δσ = 150 kPasandclayCc​ = 0.4e0​ = 1.15σ′0​ = 45 kPa2.5 mwater table

A 2.5 m thick layer of normally consolidated clay (Cc = 0.4, e₀ = 1.15) has an effective vertical stress of 45 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 150 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 2.5 mCc = 0.4e0 = 1.15σ′0 = 45 kPaΔσ = 150 kPa
S = mm
3.Medium
Δσ = 10 kPasandclayCc​ = 0.25, Cr​ = 0.02e0​ = 0.9σ′0​ = 50 kPaσ′p​ = 120 kPa3.5 mwater table

A 3.5 m thick overconsolidated clay layer has Cc = 0.25, Cr = 0.02 and e₀ = 0.9. At its mid-depth the effective vertical stress is 50 kPa and the preconsolidation pressure is 120 kPa. A new building adds 10 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3.5 mCc = 0.25Cr = 0.02e0 = 0.9σ′0 = 50 kPaσ′p = 120 kPaΔσ = 10 kPa
S = mm
4.Medium
Δσ = 120 kPasandclayCc​ = 0.2, Cr​ = 0.04e0​ = 1.1σ′0​ = 95 kPaσ′p​ = 165 kPa3.5 mwater table

A 3.5 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.04 and e₀ = 1.1. At its mid-depth the effective vertical stress is 95 kPa and the preconsolidation pressure is 165 kPa. A new building adds 120 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3.5 mCc = 0.2Cr = 0.04e0 = 1.1σ′0 = 95 kPaσ′p = 165 kPaΔσ = 120 kPa
S = mm
5.Hard
sandclayH = 6.5 mcv​ = 2 m²/year6.5 mimpervious rockwater table

A clay layer 6.5 m thick has a coefficient of consolidation cv = 2 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 6.5 mcv = 2 m²/yearU = 80%Tv = 0.567single drainage
t = years
6.Hard
sandclayH = 3 m3 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 20 mm thick, drained at the top and bottom, reaches 50% consolidation in 12 min. In the field the same clay forms a layer 3 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 20 mmtlab = 12 minH = 3 mfield: single drainage
t = days

Answer key

  1. 1. S = 220.1 mm
  2. 2. S = 296.2 mm
  3. 3. S = 2.917 mm
  4. 4. S = 54.3 mm
  5. 5. t = 11.98 years
  6. 6. t = 750 days

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