A 9 m thick normally consolidated clay layer (γsat = 19 kN/m³, Cc = 0.5, e₀ = 0.8) lies below 2.5 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 100 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
Consolidation settlement worksheet with answers
A 9 m thick normally consolidated clay layer (γsat = 19 kN/m³, Cc = 0.25, e₀ = 1.3) lies below 5 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 45 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
A 5.5 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.05 and e₀ = 0.85. At its mid-depth the effective vertical stress is 90 kPa and the overconsolidation ratio is OCR = 2.5. A new building adds 90 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A 4 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.03 and e₀ = 0.65. At its mid-depth the effective vertical stress is 80 kPa and the overconsolidation ratio is OCR = 2.5. A new building adds 160 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A clay layer 5 m thick has a coefficient of consolidation cv = 3 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 90% average consolidation the time factor is Tv = 0.848. How many years t does the layer take to reach 90% consolidation?
A clay layer 7.5 m thick has a coefficient of consolidation cv = 0.8 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 50% average consolidation the time factor is Tv = 0.197. How many years t does the layer take to reach 50% consolidation?
Answer key
- 1. S = 835.1 mm
- 2. S = 125.2 mm
- 3. S = 44.75 mm
- 4. S = 67.33 mm
- 5. t = 1.767 years
- 6. t = 13.85 years
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