Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 120 kPasandclayCc​ = 0.6e0​ = 0.9σ′0​ = 150 kPa7.5 mwater table

A 7.5 m thick layer of normally consolidated clay (Cc = 0.6, e₀ = 0.9) has an effective vertical stress of 150 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 120 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 7.5 mCc = 0.6e0 = 0.9σ′0 = 150 kPaΔσ = 120 kPa
S = mm
2.Easy
Δσ = 85 kPasandγ = 18 kN/m³4 mclayγsat​ = 18 kN/m³Cc​ = 0.35, e0​ = 1.410 mwater tableX

A 10 m thick normally consolidated clay layer (γsat = 18 kN/m³, Cc = 0.35, e₀ = 1.4) lies below 4 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 85 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 4 m, γ = 18 kN/m³clay: H = 10 m, γsat = 18 kN/m³γw = 9.81 kN/m³Cc = 0.35e0 = 1.4Δσ = 85 kPa
S = mm
3.Medium
Δσ = 35 kPasandclayCc​ = 0.45, Cr​ = 0.05e0​ = 1.15σ′0​ = 115 kPaσ′p​ = 175 kPa3 mwater table

A 3 m thick overconsolidated clay layer has Cc = 0.45, Cr = 0.05 and e₀ = 1.15. At its mid-depth the effective vertical stress is 115 kPa and the preconsolidation pressure is 175 kPa. A new building adds 35 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.45Cr = 0.05e0 = 1.15σ′0 = 115 kPaσ′p = 175 kPaΔσ = 35 kPa
S = mm
4.Medium
Δσ = 210 kPasandclayCc​ = 0.5, Cr​ = 0.06e0​ = 1.2σ′0​ = 95 kPaσ′p​ = 195 kPa8 mwater table

An 8 m thick overconsolidated clay layer has Cc = 0.5, Cr = 0.06 and e₀ = 1.2. At its mid-depth the effective vertical stress is 95 kPa and the preconsolidation pressure is 195 kPa. A new building adds 210 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 8 mCc = 0.5Cr = 0.06e0 = 1.2σ′0 = 95 kPaσ′p = 195 kPaΔσ = 210 kPa
S = mm
5.Hard
sandclayH = 2.5 mcv​ = 1 m²/year2.5 mimpervious rockwater table

A clay layer 2.5 m thick has a coefficient of consolidation cv = 1 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 60% average consolidation the time factor is Tv = 0.287. How many years t does the layer take to reach 60% consolidation?

H = 2.5 mcv = 1 m²/yearU = 60%Tv = 0.287single drainage
t = years
6.Hard
sandclayH = 8.5 mcv​ = 4 m²/year8.5 mimpervious rockwater table

A clay layer 8.5 m thick has a coefficient of consolidation cv = 4 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 70% average consolidation the time factor is Tv = 0.403. How many years t does the layer take to reach 70% consolidation?

H = 8.5 mcv = 4 m²/yearU = 70%Tv = 0.403single drainage
t = years

Answer key

  1. 1. S = 604.6 mm
  2. 2. S = 355.4 mm
  3. 3. S = 8.051 mm
  4. 4. S = 421.4 mm
  5. 5. t = 1.794 years
  6. 6. t = 7.279 years

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