A 9 m thick normally consolidated clay layer (γsat = 19 kN/m³, Cc = 0.5, e₀ = 0.8) lies below 6 m of sand (γ = 19 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 130 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
Consolidation settlement worksheet with answers
A 3 m thick normally consolidated clay layer (γsat = 18.5 kN/m³, Cc = 0.2, e₀ = 0.95) lies below 5 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 150 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
A 4.5 m thick overconsolidated clay layer has Cc = 0.4, Cr = 0.06 and e₀ = 0.9. At its mid-depth the effective vertical stress is 75 kPa and the preconsolidation pressure is 155 kPa. A new building adds 15 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A 5.5 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.02 and e₀ = 0.85. At its mid-depth the effective vertical stress is 40 kPa and the preconsolidation pressure is 70 kPa. A new building adds 100 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A clay layer 6.5 m thick has a coefficient of consolidation cv = 3 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 70% average consolidation the time factor is Tv = 0.403. How many years t does the layer take to reach 70% consolidation?
A clay layer 7.5 m thick has a coefficient of consolidation cv = 1 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 90% average consolidation the time factor is Tv = 0.848. How many years t does the layer take to reach 90% consolidation?
Answer key
- 1. S = 660.2 mm
- 2. S = 120.1 mm
- 3. S = 11.25 mm
- 4. S = 282.9 mm
- 5. t = 5.676 years
- 6. t = 11.92 years
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