Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 115 kPasandγ = 18 kN/m³3.5 mclayγsat​ = 18.5 kN/m³Cc​ = 0.45, e0​ = 1.358 mwater tableX

An 8 m thick normally consolidated clay layer (γsat = 18.5 kN/m³, Cc = 0.45, e₀ = 1.35) lies below 3.5 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 115 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 3.5 m, γ = 18 kN/m³clay: H = 8 m, γsat = 18.5 kN/m³γw = 9.81 kN/m³Cc = 0.45e0 = 1.35Δσ = 115 kPa
S = mm
2.Easy
Δσ = 35 kPasandclayCc​ = 0.5e0​ = 1.3σ′0​ = 55 kPa5 mwater table

A 5 m thick layer of normally consolidated clay (Cc = 0.5, e₀ = 1.3) has an effective vertical stress of 55 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 35 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 5 mCc = 0.5e0 = 1.3σ′0 = 55 kPaΔσ = 35 kPa
S = mm
3.Medium
Δσ = 70 kPasandclayCc​ = 0.35, Cr​ = 0.02e0​ = 0.65σ′0​ = 65 kPaOCR = 1.56 mwater table

A 6 m thick overconsolidated clay layer has Cc = 0.35, Cr = 0.02 and e₀ = 0.65. At its mid-depth the effective vertical stress is 65 kPa and the overconsolidation ratio is OCR = 1.5. A new building adds 70 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 6 mCc = 0.35Cr = 0.02e0 = 0.65σ′0 = 65 kPaOCR = 1.5Δσ = 70 kPa
S = mm
4.Medium
Δσ = 140 kPasandclayCc​ = 0.3, Cr​ = 0.04e0​ = 1.1σ′0​ = 60 kPaOCR = 23 mwater table

A 3 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.04 and e₀ = 1.1. At its mid-depth the effective vertical stress is 60 kPa and the overconsolidation ratio is OCR = 2. A new building adds 140 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.3Cr = 0.04e0 = 1.1σ′0 = 60 kPaOCR = 2Δσ = 140 kPa
S = mm
5.Hard
sandclayH = 5 mcv​ = 4 m²/year5 msandwater table

A clay layer 5 m thick has a coefficient of consolidation cv = 4 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 70% average consolidation the time factor is Tv = 0.403. How many years t does the layer take to reach 70% consolidation?

H = 5 mcv = 4 m²/yearU = 70%Tv = 0.403double drainage
t = years
6.Hard
sandclayH = 3.5 mcv​ = 3 m²/year3.5 msandwater table

A clay layer 3.5 m thick has a coefficient of consolidation cv = 3 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 90% average consolidation the time factor is Tv = 0.848. How many years t does the layer take to reach 90% consolidation?

H = 3.5 mcv = 3 m²/yearU = 90%Tv = 0.848double drainage
t = years

Answer key

  1. 1. S = 517.4 mm
  2. 2. S = 232.5 mm
  3. 3. S = 192.7 mm
  4. 4. S = 112.3 mm
  5. 5. t = 0.6297 years
  6. 6. t = 0.8657 years

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