Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 150 kPasandγ = 18 kN/m³3.5 mclayγsat​ = 19.5 kN/m³Cc​ = 0.4, e0​ = 1.33 mwater tableX

A 3 m thick normally consolidated clay layer (γsat = 19.5 kN/m³, Cc = 0.4, e₀ = 1.3) lies below 3.5 m of sand (γ = 18 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 150 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 3.5 m, γ = 18 kN/m³clay: H = 3 m, γsat = 19.5 kN/m³γw = 9.81 kN/m³Cc = 0.4e0 = 1.3Δσ = 150 kPa
S = mm
2.Easy
Δσ = 45 kPasandclayCc​ = 0.35e0​ = 1.05σ′0​ = 115 kPa2 mwater table

A 2 m thick layer of normally consolidated clay (Cc = 0.35, e₀ = 1.05) has an effective vertical stress of 115 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 45 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 2 mCc = 0.35e0 = 1.05σ′0 = 115 kPaΔσ = 45 kPa
S = mm
3.Medium
Δσ = 180 kPasandclayCc​ = 0.45, Cr​ = 0.02e0​ = 0.6σ′0​ = 75 kPaσ′p​ = 135 kPa4.5 mwater table

A 4.5 m thick overconsolidated clay layer has Cc = 0.45, Cr = 0.02 and e₀ = 0.6. At its mid-depth the effective vertical stress is 75 kPa and the preconsolidation pressure is 135 kPa. A new building adds 180 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 4.5 mCc = 0.45Cr = 0.02e0 = 0.6σ′0 = 75 kPaσ′p = 135 kPaΔσ = 180 kPa
S = mm
4.Medium
Δσ = 210 kPasandclayCc​ = 0.25, Cr​ = 0.05e0​ = 0.7σ′0​ = 120 kPaσ′p​ = 190 kPa3 mwater table

A 3 m thick overconsolidated clay layer has Cc = 0.25, Cr = 0.05 and e₀ = 0.7. At its mid-depth the effective vertical stress is 120 kPa and the preconsolidation pressure is 190 kPa. A new building adds 210 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.25Cr = 0.05e0 = 0.7σ′0 = 120 kPaσ′p = 190 kPaΔσ = 210 kPa
S = mm
5.Hard
sandclayH = 6.5 mcv​ = 4 m²/year6.5 msandwater table

A clay layer 6.5 m thick has a coefficient of consolidation cv = 4 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 6.5 mcv = 4 m²/yearU = 80%Tv = 0.567double drainage
t = years
6.Hard
sandclayH = 3 mcv​ = 2 m²/year3 msandwater table

A clay layer 3 m thick has a coefficient of consolidation cv = 2 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 70% average consolidation the time factor is Tv = 0.403. How many years t does the layer take to reach 70% consolidation?

H = 3 mcv = 2 m²/yearU = 70%Tv = 0.403double drainage
t = years

Answer key

  1. 1. S = 243.9 mm
  2. 2. S = 48.97 mm
  3. 3. S = 363.9 mm
  4. 4. S = 123.4 mm
  5. 5. t = 1.497 years
  6. 6. t = 0.4534 years

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