Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 20 kPasandclayCc​ = 0.6e0​ = 1.15σ′0​ = 65 kPa8 mwater table

An 8 m thick layer of normally consolidated clay (Cc = 0.6, e₀ = 1.15) has an effective vertical stress of 65 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 20 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 8 mCc = 0.6e0 = 1.15σ′0 = 65 kPaΔσ = 20 kPa
S = mm
2.Easy
Δσ = 35 kPasandγ = 17 kN/m³3.5 mclayγsat​ = 17.5 kN/m³Cc​ = 0.15, e0​ = 1.259 mwater tableX

A 9 m thick normally consolidated clay layer (γsat = 17.5 kN/m³, Cc = 0.15, e₀ = 1.25) lies below 3.5 m of sand (γ = 17 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 35 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 3.5 m, γ = 17 kN/m³clay: H = 9 m, γsat = 17.5 kN/m³γw = 9.81 kN/m³Cc = 0.15e0 = 1.25Δσ = 35 kPa
S = mm
3.Medium
Δσ = 220 kPasandclayCc​ = 0.45, Cr​ = 0.06e0​ = 0.85σ′0​ = 115 kPaσ′p​ = 225 kPa3 mwater table

A 3 m thick overconsolidated clay layer has Cc = 0.45, Cr = 0.06 and e₀ = 0.85. At its mid-depth the effective vertical stress is 115 kPa and the preconsolidation pressure is 225 kPa. A new building adds 220 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.45Cr = 0.06e0 = 0.85σ′0 = 115 kPaσ′p = 225 kPaΔσ = 220 kPa
S = mm
4.Medium
Δσ = 25 kPasandclayCc​ = 0.5, Cr​ = 0.06e0​ = 1σ′0​ = 55 kPaσ′p​ = 85 kPa5.5 mwater table

A 5.5 m thick overconsolidated clay layer has Cc = 0.5, Cr = 0.06 and e₀ = 1. At its mid-depth the effective vertical stress is 55 kPa and the preconsolidation pressure is 85 kPa. A new building adds 25 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 5.5 mCc = 0.5Cr = 0.06e0 = 1σ′0 = 55 kPaσ′p = 85 kPaΔσ = 25 kPa
S = mm
5.Hard
sandclayH = 2.5 mcv​ = 1.2 m²/year2.5 msandwater table

A clay layer 2.5 m thick has a coefficient of consolidation cv = 1.2 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 50% average consolidation the time factor is Tv = 0.197. How many years t does the layer take to reach 50% consolidation?

H = 2.5 mcv = 1.2 m²/yearU = 50%Tv = 0.197double drainage
t = years
6.Hard
sandclayH = 4.5 m4.5 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 20 mm thick, drained at the top and bottom, reaches 50% consolidation in 12 min. In the field the same clay forms a layer 4.5 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 20 mmtlab = 12 minH = 4.5 mfield: single drainage
t = days

Answer key

  1. 1. S = 260.1 mm
  2. 2. S = 82.4 mm
  3. 3. S = 154.5 mm
  4. 4. S = 26.85 mm
  5. 5. t = 0.2565 years
  6. 6. t = 1688 days

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