Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 115 kPasandγ = 17.5 kN/m³3.5 mclayγsat​ = 17.5 kN/m³Cc​ = 0.45, e0​ = 1.33 mwater tableX

A 3 m thick normally consolidated clay layer (γsat = 17.5 kN/m³, Cc = 0.45, e₀ = 1.3) lies below 3.5 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 115 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 3.5 m, γ = 17.5 kN/m³clay: H = 3 m, γsat = 17.5 kN/m³γw = 9.81 kN/m³Cc = 0.45e0 = 1.3Δσ = 115 kPa
S = mm
2.Easy
Δσ = 110 kPasandclayCc​ = 0.3e0​ = 1.35σ′0​ = 130 kPa7 mwater table

A 7 m thick layer of normally consolidated clay (Cc = 0.3, e₀ = 1.35) has an effective vertical stress of 130 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 110 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 7 mCc = 0.3e0 = 1.35σ′0 = 130 kPaΔσ = 110 kPa
S = mm
3.Medium
Δσ = 25 kPasandclayCc​ = 0.2, Cr​ = 0.06e0​ = 1σ′0​ = 60 kPaσ′p​ = 180 kPa5 mwater table

A 5 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.06 and e₀ = 1. At its mid-depth the effective vertical stress is 60 kPa and the preconsolidation pressure is 180 kPa. A new building adds 25 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 5 mCc = 0.2Cr = 0.06e0 = 1σ′0 = 60 kPaσ′p = 180 kPaΔσ = 25 kPa
S = mm
4.Medium
Δσ = 120 kPasandclayCc​ = 0.35, Cr​ = 0.05e0​ = 1.05σ′0​ = 120 kPaσ′p​ = 210 kPa4.5 mwater table

A 4.5 m thick overconsolidated clay layer has Cc = 0.35, Cr = 0.05 and e₀ = 1.05. At its mid-depth the effective vertical stress is 120 kPa and the preconsolidation pressure is 210 kPa. A new building adds 120 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 4.5 mCc = 0.35Cr = 0.05e0 = 1.05σ′0 = 120 kPaσ′p = 210 kPaΔσ = 120 kPa
S = mm
5.Hard
sandclayH = 3 mcv​ = 3 m²/year3 msandwater table

A clay layer 3 m thick has a coefficient of consolidation cv = 3 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 3 mcv = 3 m²/yearU = 80%Tv = 0.567double drainage
t = years
6.Hard
sandclayH = 6.5 mcv​ = 0.5 m²/year6.5 msandwater table

A clay layer 6.5 m thick has a coefficient of consolidation cv = 0.5 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 90% average consolidation the time factor is Tv = 0.848. How many years t does the layer take to reach 90% consolidation?

H = 6.5 mcv = 0.5 m²/yearU = 90%Tv = 0.848double drainage
t = years

Answer key

  1. 1. S = 241.6 mm
  2. 2. S = 237.9 mm
  3. 3. S = 22.69 mm
  4. 4. S = 71.23 mm
  5. 5. t = 0.4252 years
  6. 6. t = 17.91 years

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