Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 40 kPasandclayCc​ = 0.3e0​ = 0.65σ′0​ = 45 kPa3 mwater table

A 3 m thick layer of normally consolidated clay (Cc = 0.3, e₀ = 0.65) has an effective vertical stress of 45 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 40 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.3e0 = 0.65σ′0 = 45 kPaΔσ = 40 kPa
S = mm
2.Easy
Δσ = 30 kPasandclayCc​ = 0.3e0​ = 1.1σ′0​ = 120 kPa2.5 mwater table

A 2.5 m thick layer of normally consolidated clay (Cc = 0.3, e₀ = 1.1) has an effective vertical stress of 120 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 30 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 2.5 mCc = 0.3e0 = 1.1σ′0 = 120 kPaΔσ = 30 kPa
S = mm
3.Medium
Δσ = 190 kPasandclayCc​ = 0.3, Cr​ = 0.06e0​ = 0.95σ′0​ = 65 kPaσ′p​ = 145 kPa8 mwater table

An 8 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.06 and e₀ = 0.95. At its mid-depth the effective vertical stress is 65 kPa and the preconsolidation pressure is 145 kPa. A new building adds 190 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 8 mCc = 0.3Cr = 0.06e0 = 0.95σ′0 = 65 kPaσ′p = 145 kPaΔσ = 190 kPa
S = mm
4.Medium
Δσ = 110 kPasandclayCc​ = 0.3, Cr​ = 0.02e0​ = 1.15σ′0​ = 95 kPaσ′p​ = 135 kPa3 mwater table

A 3 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.02 and e₀ = 1.15. At its mid-depth the effective vertical stress is 95 kPa and the preconsolidation pressure is 135 kPa. A new building adds 110 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.3Cr = 0.02e0 = 1.15σ′0 = 95 kPaσ′p = 135 kPaΔσ = 110 kPa
S = mm
5.Hard
sandclayH = 8.5 m8.5 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 25 mm thick, drained at the top and bottom, reaches 50% consolidation in 10 min. In the field the same clay forms a layer 8.5 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 25 mmtlab = 10 minH = 8.5 mfield: single drainage
t = days
6.Hard
sandclayH = 5 mcv​ = 2.5 m²/year5 msandwater table

A clay layer 5 m thick has a coefficient of consolidation cv = 2.5 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 60% average consolidation the time factor is Tv = 0.287. How many years t does the layer take to reach 60% consolidation?

H = 5 mcv = 2.5 m²/yearU = 60%Tv = 0.287double drainage
t = years

Answer key

  1. 1. S = 150.7 mm
  2. 2. S = 34.61 mm
  3. 3. S = 387.5 mm
  4. 4. S = 80.2 mm
  5. 5. t = 3211 days
  6. 6. t = 0.7175 years

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