Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 150 kPasandγ = 17.5 kN/m³5 mclayγsat​ = 19.5 kN/m³Cc​ = 0.4, e0​ = 1.059 mwater tableX

A 9 m thick normally consolidated clay layer (γsat = 19.5 kN/m³, Cc = 0.4, e₀ = 1.05) lies below 5 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 150 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 5 m, γ = 17.5 kN/m³clay: H = 9 m, γsat = 19.5 kN/m³γw = 9.81 kN/m³Cc = 0.4e0 = 1.05Δσ = 150 kPa
S = mm
2.Easy
Δσ = 45 kPasandclayCc​ = 0.6e0​ = 0.8σ′0​ = 85 kPa8.5 mwater table

An 8.5 m thick layer of normally consolidated clay (Cc = 0.6, e₀ = 0.8) has an effective vertical stress of 85 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 45 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 8.5 mCc = 0.6e0 = 0.8σ′0 = 85 kPaΔσ = 45 kPa
S = mm
3.Medium
Δσ = 50 kPasandclayCc​ = 0.25, Cr​ = 0.03e0​ = 0.6σ′0​ = 95 kPaσ′p​ = 215 kPa2 mwater table

A 2 m thick overconsolidated clay layer has Cc = 0.25, Cr = 0.03 and e₀ = 0.6. At its mid-depth the effective vertical stress is 95 kPa and the preconsolidation pressure is 215 kPa. A new building adds 50 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 2 mCc = 0.25Cr = 0.03e0 = 0.6σ′0 = 95 kPaσ′p = 215 kPaΔσ = 50 kPa
S = mm
4.Medium
Δσ = 170 kPasandclayCc​ = 0.3, Cr​ = 0.05e0​ = 1.1σ′0​ = 90 kPaσ′p​ = 210 kPa7 mwater table

A 7 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.05 and e₀ = 1.1. At its mid-depth the effective vertical stress is 90 kPa and the preconsolidation pressure is 210 kPa. A new building adds 170 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 7 mCc = 0.3Cr = 0.05e0 = 1.1σ′0 = 90 kPaσ′p = 210 kPaΔσ = 170 kPa
S = mm
5.Hard
sandclayH = 5 mcv​ = 1.5 m²/year5 mimpervious rockwater table

A clay layer 5 m thick has a coefficient of consolidation cv = 1.5 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 5 mcv = 1.5 m²/yearU = 80%Tv = 0.567single drainage
t = years
6.Hard
sandclayH = 8.5 mcv​ = 1.2 m²/year8.5 mimpervious rockwater table

A clay layer 8.5 m thick has a coefficient of consolidation cv = 1.2 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 70% average consolidation the time factor is Tv = 0.403. How many years t does the layer take to reach 70% consolidation?

H = 8.5 mcv = 1.2 m²/yearU = 70%Tv = 0.403single drainage
t = years

Answer key

  1. 1. S = 581.7 mm
  2. 2. S = 522.8 mm
  3. 3. S = 6.887 mm
  4. 4. S = 154.1 mm
  5. 5. t = 9.45 years
  6. 6. t = 24.26 years

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