An 8 m thick normally consolidated clay layer (γsat = 19 kN/m³, Cc = 0.6, e₀ = 0.65) lies below 6 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 150 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
Consolidation settlement worksheet with answers
A 4 m thick normally consolidated clay layer (γsat = 19.5 kN/m³, Cc = 0.15, e₀ = 1.4) lies below 2.5 m of sand (γ = 17.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 65 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.
A 3 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.04 and e₀ = 1. At its mid-depth the effective vertical stress is 115 kPa and the preconsolidation pressure is 195 kPa. A new building adds 10 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
A 6 m thick overconsolidated clay layer has Cc = 0.5, Cr = 0.03 and e₀ = 1.1. At its mid-depth the effective vertical stress is 95 kPa and the overconsolidation ratio is OCR = 1.5. A new building adds 90 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.
In a laboratory oedometer test, a clay specimen 25 mm thick, drained at the top and bottom, reaches 50% consolidation in 12 min. In the field the same clay forms a layer 3.5 m thick. It lies between two sand layers, so water drains out at the top and the bottom. How many days t does the field layer take to reach 50% consolidation?
A clay layer 4.5 m thick has a coefficient of consolidation cv = 3 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 60% average consolidation the time factor is Tv = 0.287. How many years t does the layer take to reach 60% consolidation?
Answer key
- 1. S = 911.9 mm
- 2. S = 76.85 mm
- 3. S = 2.173 mm
- 4. S = 177 mm
- 5. t = 163.3 days
- 6. t = 1.937 years
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