Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 140 kPasandclayCc​ = 0.35e0​ = 1.2σ′0​ = 115 kPa8.5 mwater table

An 8.5 m thick layer of normally consolidated clay (Cc = 0.35, e₀ = 1.2) has an effective vertical stress of 115 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 140 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 8.5 mCc = 0.35e0 = 1.2σ′0 = 115 kPaΔσ = 140 kPa
S = mm
2.Easy
Δσ = 35 kPasandclayCc​ = 0.6e0​ = 0.65σ′0​ = 115 kPa3 mwater table

A 3 m thick layer of normally consolidated clay (Cc = 0.6, e₀ = 0.65) has an effective vertical stress of 115 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 35 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 3 mCc = 0.6e0 = 0.65σ′0 = 115 kPaΔσ = 35 kPa
S = mm
3.Medium
Δσ = 130 kPasandclayCc​ = 0.3, Cr​ = 0.05e0​ = 1.2σ′0​ = 40 kPaOCR = 2.53.5 mwater table

A 3.5 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.05 and e₀ = 1.2. At its mid-depth the effective vertical stress is 40 kPa and the overconsolidation ratio is OCR = 2.5. A new building adds 130 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3.5 mCc = 0.3Cr = 0.05e0 = 1.2σ′0 = 40 kPaOCR = 2.5Δσ = 130 kPa
S = mm
4.Medium
Δσ = 140 kPasandclayCc​ = 0.4, Cr​ = 0.04e0​ = 1σ′0​ = 90 kPaOCR = 36 mwater table

A 6 m thick overconsolidated clay layer has Cc = 0.4, Cr = 0.04 and e₀ = 1. At its mid-depth the effective vertical stress is 90 kPa and the overconsolidation ratio is OCR = 3. A new building adds 140 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 6 mCc = 0.4Cr = 0.04e0 = 1σ′0 = 90 kPaOCR = 3Δσ = 140 kPa
S = mm
5.Hard
sandclayH = 6 m6 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 19 mm thick, drained at the top and bottom, reaches 50% consolidation in 12 min. In the field the same clay forms a layer 6 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 19 mmtlab = 12 minH = 6 mfield: single drainage
t = days
6.Hard
sandclayH = 2.5 mcv​ = 2 m²/year2.5 mimpervious rockwater table

A clay layer 2.5 m thick has a coefficient of consolidation cv = 2 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 2.5 mcv = 2 m²/yearU = 80%Tv = 0.567single drainage
t = years

Answer key

  1. 1. S = 467.7 mm
  2. 2. S = 125.9 mm
  3. 3. S = 141.6 mm
  4. 4. S = 48.9 mm
  5. 5. t = 3324 days
  6. 6. t = 1.772 years

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