Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 140 kPasandγ = 18.5 kN/m³3.5 mclayγsat​ = 18.5 kN/m³Cc​ = 0.15, e0​ = 0.610 mwater tableX

A 10 m thick normally consolidated clay layer (γsat = 18.5 kN/m³, Cc = 0.15, e₀ = 0.6) lies below 3.5 m of sand (γ = 18.5 kN/m³). The water table is at the top of the clay; use γw = 9.81 kN/m³. A wide fill raises the vertical stress throughout the clay by 140 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

sand: Hs = 3.5 m, γ = 18.5 kN/m³clay: H = 10 m, γsat = 18.5 kN/m³γw = 9.81 kN/m³Cc = 0.15e0 = 0.6Δσ = 140 kPa
S = mm
2.Easy
Δσ = 105 kPasandclayCc​ = 0.25e0​ = 1.1σ′0​ = 80 kPa5.5 mwater table

A 5.5 m thick layer of normally consolidated clay (Cc = 0.25, e₀ = 1.1) has an effective vertical stress of 80 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 105 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 5.5 mCc = 0.25e0 = 1.1σ′0 = 80 kPaΔσ = 105 kPa
S = mm
3.Medium
Δσ = 50 kPasandclayCc​ = 0.4, Cr​ = 0.03e0​ = 1.1σ′0​ = 50 kPaσ′p​ = 80 kPa2.5 mwater table

A 2.5 m thick overconsolidated clay layer has Cc = 0.4, Cr = 0.03 and e₀ = 1.1. At its mid-depth the effective vertical stress is 50 kPa and the preconsolidation pressure is 80 kPa. A new building adds 50 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 2.5 mCc = 0.4Cr = 0.03e0 = 1.1σ′0 = 50 kPaσ′p = 80 kPaΔσ = 50 kPa
S = mm
4.Medium
Δσ = 220 kPasandclayCc​ = 0.2, Cr​ = 0.06e0​ = 0.7σ′0​ = 45 kPaσ′p​ = 115 kPa3.5 mwater table

A 3.5 m thick overconsolidated clay layer has Cc = 0.2, Cr = 0.06 and e₀ = 0.7. At its mid-depth the effective vertical stress is 45 kPa and the preconsolidation pressure is 115 kPa. A new building adds 220 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 3.5 mCc = 0.2Cr = 0.06e0 = 0.7σ′0 = 45 kPaσ′p = 115 kPaΔσ = 220 kPa
S = mm
5.Hard
sandclayH = 2.5 mcv​ = 0.8 m²/year2.5 mimpervious rockwater table

A clay layer 2.5 m thick has a coefficient of consolidation cv = 0.8 m²/year. It lies on impervious rock, with sand above it, so water drains out only at the top. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 2.5 mcv = 0.8 m²/yearU = 80%Tv = 0.567single drainage
t = years
6.Hard
sandclayH = 7 mcv​ = 0.8 m²/year7 msandwater table

A clay layer 7 m thick has a coefficient of consolidation cv = 0.8 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 80% average consolidation the time factor is Tv = 0.567. How many years t does the layer take to reach 80% consolidation?

H = 7 mcv = 0.8 m²/yearU = 80%Tv = 0.567double drainage
t = years

Answer key

  1. 1. S = 338 mm
  2. 2. S = 238.4 mm
  3. 3. S = 53.44 mm
  4. 4. S = 199.6 mm
  5. 5. t = 4.43 years
  6. 6. t = 8.682 years

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