Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 115 kPasandclayCc​ = 0.5e0​ = 1.3σ′0​ = 65 kPa5.5 mwater table

A 5.5 m thick layer of normally consolidated clay (Cc = 0.5, e₀ = 1.3) has an effective vertical stress of 65 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 115 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 5.5 mCc = 0.5e0 = 1.3σ′0 = 65 kPaΔσ = 115 kPa
S = mm
2.Easy
Δσ = 95 kPasandclayCc​ = 0.25e0​ = 1.4σ′0​ = 140 kPa7 mwater table

A 7 m thick layer of normally consolidated clay (Cc = 0.25, e₀ = 1.4) has an effective vertical stress of 140 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 95 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 7 mCc = 0.25e0 = 1.4σ′0 = 140 kPaΔσ = 95 kPa
S = mm
3.Medium
Δσ = 70 kPasandclayCc​ = 0.4, Cr​ = 0.04e0​ = 0.75σ′0​ = 100 kPaOCR = 2.57.5 mwater table

A 7.5 m thick overconsolidated clay layer has Cc = 0.4, Cr = 0.04 and e₀ = 0.75. At its mid-depth the effective vertical stress is 100 kPa and the overconsolidation ratio is OCR = 2.5. A new building adds 70 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 7.5 mCc = 0.4Cr = 0.04e0 = 0.75σ′0 = 100 kPaOCR = 2.5Δσ = 70 kPa
S = mm
4.Medium
Δσ = 130 kPasandclayCc​ = 0.5, Cr​ = 0.04e0​ = 1.15σ′0​ = 65 kPaOCR = 22.5 mwater table

A 2.5 m thick overconsolidated clay layer has Cc = 0.5, Cr = 0.04 and e₀ = 1.15. At its mid-depth the effective vertical stress is 65 kPa and the overconsolidation ratio is OCR = 2. A new building adds 130 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 2.5 mCc = 0.5Cr = 0.04e0 = 1.15σ′0 = 65 kPaOCR = 2Δσ = 130 kPa
S = mm
5.Hard
sandclayH = 8 mcv​ = 0.5 m²/year8 msandwater table

A clay layer 8 m thick has a coefficient of consolidation cv = 0.5 m²/year. It lies between two sand layers, so water drains out at the top and the bottom. For 90% average consolidation the time factor is Tv = 0.848. How many years t does the layer take to reach 90% consolidation?

H = 8 mcv = 0.5 m²/yearU = 90%Tv = 0.848double drainage
t = years
6.Hard
sandclayH = 2 m2 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 25 mm thick, drained at the top and bottom, reaches 50% consolidation in 10 min. In the field the same clay forms a layer 2 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 25 mmtlab = 10 minH = 2 mfield: single drainage
t = days

Answer key

  1. 1. S = 528.9 mm
  2. 2. S = 164 mm
  3. 3. S = 39.51 mm
  4. 4. S = 116.4 mm
  5. 5. t = 27.14 years
  6. 6. t = 177.8 days

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