Consolidation settlement worksheet with answers

Free printable Consolidation settlement worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Δσ = 40 kPasandclayCc​ = 0.6e0​ = 0.9σ′0​ = 125 kPa2.5 mwater table

A 2.5 m thick layer of normally consolidated clay (Cc = 0.6, e₀ = 0.9) has an effective vertical stress of 125 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 40 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 2.5 mCc = 0.6e0 = 0.9σ′0 = 125 kPaΔσ = 40 kPa
S = mm
2.Easy
Δσ = 140 kPasandclayCc​ = 0.5e0​ = 0.65σ′0​ = 55 kPa6 mwater table

A 6 m thick layer of normally consolidated clay (Cc = 0.5, e₀ = 0.65) has an effective vertical stress of 55 kPa at its mid-depth. A wide fill raises the vertical stress in the clay by 140 kPa. Treat the layer as one sublayer with the stresses at its mid-depth. Find the primary consolidation settlement S in mm.

H = 6 mCc = 0.5e0 = 0.65σ′0 = 55 kPaΔσ = 140 kPa
S = mm
3.Medium
Δσ = 110 kPasandclayCc​ = 0.4, Cr​ = 0.06e0​ = 1σ′0​ = 75 kPaOCR = 34.5 mwater table

A 4.5 m thick overconsolidated clay layer has Cc = 0.4, Cr = 0.06 and e₀ = 1. At its mid-depth the effective vertical stress is 75 kPa and the overconsolidation ratio is OCR = 3. A new building adds 110 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 4.5 mCc = 0.4Cr = 0.06e0 = 1σ′0 = 75 kPaOCR = 3Δσ = 110 kPa
S = mm
4.Medium
Δσ = 220 kPasandclayCc​ = 0.3, Cr​ = 0.02e0​ = 0.75σ′0​ = 105 kPaσ′p​ = 185 kPa7.5 mwater table

A 7.5 m thick overconsolidated clay layer has Cc = 0.3, Cr = 0.02 and e₀ = 0.75. At its mid-depth the effective vertical stress is 105 kPa and the preconsolidation pressure is 185 kPa. A new building adds 220 kPa of vertical stress at mid-depth. Find the primary consolidation settlement S in mm.

H = 7.5 mCc = 0.3Cr = 0.02e0 = 0.75σ′0 = 105 kPaσ′p = 185 kPaΔσ = 220 kPa
S = mm
5.Hard
sandclayH = 5.5 m5.5 msandwater table

In a laboratory oedometer test, a clay specimen 19 mm thick, drained at the top and bottom, reaches 50% consolidation in 4 min. In the field the same clay forms a layer 5.5 m thick. It lies between two sand layers, so water drains out at the top and the bottom. How many days t does the field layer take to reach 50% consolidation?

hlab = 19 mmtlab = 4 minH = 5.5 mfield: double drainage
t = days
6.Hard
sandclayH = 7 m7 mimpervious rockwater table

In a laboratory oedometer test, a clay specimen 25 mm thick, drained at the top and bottom, reaches 50% consolidation in 6 min. In the field the same clay forms a layer 7 m thick. It lies on impervious rock, with sand above it, so water drains out only at the top. How many days t does the field layer take to reach 50% consolidation?

hlab = 25 mmtlab = 6 minH = 7 mfield: single drainage
t = days

Answer key

  1. 1. S = 95.19 mm
  2. 2. S = 999.4 mm
  3. 3. S = 52.93 mm
  4. 4. S = 335.7 mm
  5. 5. t = 232.8 days
  6. 6. t = 1307 days

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