The sequences x[n] = {−1, 2, −1, −3} and h[n] = {2, 2, 1} both start at n = 0. Find the sample y[1] of the convolution y[n] = x[n] ∗ h[n].
Convolution & LTI systems worksheet with answers
1.Easy
x[n] = {−1, 2, −1, −3}, n = 0…3h[n] = {2, 2, 1}, n = 0…2
y[1] =
2.Easy
The sequences x[n] = {4, −2, −3} and h[n] = {3, −3} both start at n = 0. Find the largest sample ymax of y[n] = x[n] ∗ h[n].
x[n] = {4, −2, −3}, n = 0…2h[n] = {3, −3}, n = 0…1
ymax =
3.Medium
The pulse x(t) = 5 for 0 ≤ t < 2 s is convolved with h(t), a triangle that falls linearly from 2 at t = 0 to 0 at t = 2 s. Find the area Ay under y(t) = x(t) ∗ h(t).
x(t) = 5, 0 ≤ t < 2 sh(0) = 2, h(2) = 0
Ay =
4.Medium
A system has the impulse response h(t) = e−5tu(t). The input is a step x(t) = 2·u(t). Find the output y(0.1) at t = 0.1 s.
h(t) = e−5tu(t)x(t) = 2·u(t)t = 0.1 s
y(0.1) =
5.Hard
A system obeys y′(t) + 4·y(t) = 5·x(t). Find its impulse response at t = 0.05 s, h(0.05).
y′ + 4y = 5xt = 0.05 s
h(0.05) =
6.Hard
A square wave switches between 10 and 0 with period T = 10 ms (half a period at each level). Find the amplitude c1 of its Fourier component at 100 Hz.
0 … 10T = 10 msf = 100 Hz
c1 =
Answer key
- 1. y[1] = 2
- 2. ymax = 12
- 3. Ay = 20
- 4. y(0.1) = 0.1574
- 5. h(0.05) = 4.094
- 6. c1 = 6.366
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