An FIR filter computes y[n] = x[n] − x[n − 1] + 0.5·x[n − 2]. The input is x[n] = {3, 3, 1, 3} for n = 0…3 and zero elsewhere. Find the output y[2].
Convolution & LTI systems worksheet with answers
1.Easy
b = {1, −1, 0.5}x[n] = {3, 3, 1, 3}, n = 0…3
y[2] =
2.Easy
An FIR filter computes y[n] = x[n] + 0.25·x[n − 1] − 0.5·x[n − 2]. The input is x[n] = {−2, 1, 2, 1} for n = 0…3 and zero elsewhere. Find the output y[2].
b = {1, 0.25, −0.5}x[n] = {−2, 1, 2, 1}, n = 0…3
y[2] =
3.Medium
The input x(t) = 10·e−3tu(t) is applied to a system with h(t) = e−1tu(t). Find the output y(1.5) at t = 1.5 s.
x(t) = 10·e−3tu(t)h(t) = e−1tu(t)t = 1.5 s
y(1.5) =
4.Medium
The input x(t) = 10·e−2tu(t) is applied to a system with h(t) = e−1tu(t). Find the output y(0.25) at t = 0.25 s.
x(t) = 10·e−2tu(t)h(t) = e−1tu(t)t = 0.25 s
y(0.25) =
5.Hard
A square wave switches between +3 and −3 with period T = 2 ms (half a period at each level). Find the amplitude c7 of its Fourier component at 3500 Hz.
±3T = 2 msf = 3500 Hz
c7 =
6.Hard
A system obeys y[n] = 0.5·y[n − 1] + 0.5·x[n] and starts at rest. Find its impulse response sample h[4].
y[n] = 0.5y[n − 1] + 0.5x[n]x[n] = δ[n]
h[4] =
Answer key
- 1. y[2] = −0.5
- 2. y[2] = 3.25
- 3. y(1.5) = 1.06
- 4. y(0.25) = 1.723
- 5. c7 = 0.5457
- 6. h[4] = 0.03125
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