1.Easy
An electron (charge −1.602 × 10⁻¹⁹ C, mass 9.109 × 10⁻³¹ kg) is in a uniform electric field of 1300 N/C. Ignoring gravity, find the magnitude of its acceleration a.
E = 1300 N/C|q| = 1.602 × 10⁻¹⁹ Cm = 9.109 × 10⁻³¹ kg
a = m/s²
Coulomb’s law & electric fields worksheet with answers
2.Easy
Two point charges of −10 µC and +2 µC are 6 cm apart. Find the magnitude of the electric force F between them. Use k = 8.99 × 10⁹ N·m²/C².
q1 = −10 µCq2 = +2 µCr = 6 cm
F = N
3.Medium
Two identical small metal spheres carry charges of +3 µC and +10 µC. They are touched together and then put back 25 cm apart. Find the magnitude of the force F between them now. Use k = 8.99 × 10⁹ N·m²/C².
q1 = +3 µCq2 = +10 µCr = 25 cm
F = N
4.Medium
A charge of +8 µC and a charge of −10 µC are 10 cm apart. Point P lies on the line between them, 5 cm from the first charge. Find the magnitude of the electric field E at P.
q1 = +8 µCq2 = −10 µCr1 = 5 cmr2 = 5 cm
E = N/C
5.Hard
Three positive point charges sit at the corners of a right triangle: q₃ = 3 µC is at the right-angle corner, q₁ = 4 µC is 5 cm from it along one side and q₂ = 10 µC is 10 cm from it along the other side. Find the magnitude of the net electric force F on q₃.
q1 = 4 µCq2 = 10 µCq3 = 3 µCr13 = 5 cmr23 = 10 cm
F = N
6.Hard
Charges of +3 µC and +3 µC are 6 cm apart. Point P lies 4 cm from the midpoint between them, on the perpendicular bisector. Find the magnitude of the electric field E at P. Use k = 8.99 × 10⁹ N·m²/C².
q1 = +3 µCq2 = +3 µCd = 6 cmh = 4 cm
E = N/C
Answer key
- 1. a = 2.286 × 10¹⁴ m/s²
- 2. F = 49.94 N
- 3. F = 6.077 N
- 4. E = 6.473 × 10⁷ N/C
- 5. F = 50.89 N
- 6. E = 1.726 × 10⁷ N/C
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