1.Easy
A proton (charge 1.602 × 10⁻¹⁹ C, mass 1.673 × 10⁻²⁷ kg) is in a uniform electric field of 1900 N/C. Ignoring gravity, find the magnitude of its acceleration a.
E = 1900 N/C|q| = 1.602 × 10⁻¹⁹ Cm = 1.673 × 10⁻²⁷ kg
a = m/s²
Coulomb’s law & electric fields worksheet with answers
2.Easy
Find the magnitude of the electric field E at a distance of 5 cm from a point charge of −10 nC. Use k = 8.99 × 10⁹ N·m²/C².
q = −10 nCr = 5 cm
E = N/C
3.Medium
A charge of +10 µC and a charge of +4 µC are 60 cm apart. Point P lies on the line between them, 24 cm from the first charge. Find the magnitude of the electric field E at P.
q1 = +10 µCq2 = +4 µCr1 = 24 cmr2 = 36 cm
E = N/C
4.Medium
A charge of +6 µC and a charge of +1 µC are 40 cm apart. Point P lies on the line between them, 20 cm from the first charge. Find the magnitude of the electric field E at P.
q1 = +6 µCq2 = +1 µCr1 = 20 cmr2 = 20 cm
E = N/C
5.Hard
An electron enters the uniform field between two parallel plates moving parallel to them at 1.5 × 10⁷ m/s. The plates are 2 cm long and the field between them is 3700 N/C. Electron charge 1.602 × 10⁻¹⁹ C, mass 9.109 × 10⁻³¹ kg; ignore gravity. How far y is it deflected sideways when it leaves the plates? Give the answer in mm.
v₀ = 1.5 × 10⁷ m/sL = 2 cmE = 3700 N/Ce = 1.602 × 10⁻¹⁹ Cme = 9.109 × 10⁻³¹ kg
y = mm
6.Hard
Three positive point charges sit at the corners of a right triangle: q₃ = 5 µC is at the right-angle corner, q₁ = 6 µC is 10 cm from it along one side and q₂ = 5 µC is 4 cm from it along the other side. Find the magnitude of the net electric force F on q₃.
q1 = 6 µCq2 = 5 µCq3 = 5 µCr13 = 10 cmr23 = 4 cm
F = N
Answer key
- 1. a = 1.819 × 10¹¹ m/s²
- 2. E = 35960 N/C
- 3. E = 1.283 × 10⁶ N/C
- 4. E = 1.124 × 10⁶ N/C
- 5. y = 0.5784 mm
- 6. F = 143 N
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