1.Easy
A proton (charge 1.602 × 10⁻¹⁹ C, mass 1.673 × 10⁻²⁷ kg) is in a uniform electric field of 600 N/C. Ignoring gravity, find the magnitude of its acceleration a.
E = 600 N/C|q| = 1.602 × 10⁻¹⁹ Cm = 1.673 × 10⁻²⁷ kg
a = m/s²
Coulomb’s law & electric fields worksheet with answers
2.Easy
Two point charges of −2 µC and +2 µC are 5 cm apart. Find the magnitude of the electric force F between them. Use k = 8.99 × 10⁹ N·m²/C².
q1 = −2 µCq2 = +2 µCr = 5 cm
F = N
3.Medium
Two identical small metal spheres carry charges of −6 µC and +8 µC. They are touched together and then put back 10 cm apart. Find the magnitude of the force F between them now. Use k = 8.99 × 10⁹ N·m²/C².
q1 = −6 µCq2 = +8 µCr = 10 cm
F = N
4.Medium
Charges of +8 µC and +2 µC are 20 cm apart. At what distance x from the +8 µC charge, on the line between them, is the electric field zero?
q1 = +8 µCq2 = +2 µCd = 20 cm
x = cm
5.Hard
Three positive point charges sit at the corners of a right triangle: q₃ = 6 µC is at the right-angle corner, q₁ = 6 µC is 3 cm from it along one side and q₂ = 1 µC is 3 cm from it along the other side. Find the magnitude of the net electric force F on q₃.
q1 = 6 µCq2 = 1 µCq3 = 6 µCr13 = 3 cmr23 = 3 cm
F = N
6.Hard
Three positive point charges sit at the corners of a right triangle: q₃ = 4 µC is at the right-angle corner, q₁ = 1 µC is 8 cm from it along one side and q₂ = 8 µC is 5 cm from it along the other side. Find the magnitude of the net electric force F on q₃.
q1 = 1 µCq2 = 8 µCq3 = 4 µCr13 = 8 cmr23 = 5 cm
F = N
Answer key
- 1. a = 5.745 × 10¹⁰ m/s²
- 2. F = 14.38 N
- 3. F = 0.899 N
- 4. x = 13.33 cm
- 5. F = 364.6 N
- 6. F = 115.2 N
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