Data acquisition & sampling worksheet with answers

Free printable Data acquisition & sampling worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
∿01N = 1050 kHz? kbit/s

A data logger samples one channel at 50 kHz with 10-bit resolution. Find the raw data rate Rb in kbit/s.

n = 1fs = 50 kHzN = 10
Rb = kbit/s
2.Easy
SD0​D1​D2​D3​D4​D5​D6​D7​Tb​ = ?9600 Bd

A UART link runs at 9600 baud. Find the duration Tb of one bit, in µs.

baud = 9600 Bd
Tb = µs
3.Medium
tTs​ = 1/fs​f = 1.1 kHzfs​ = 2 kHz

A 1.1 kHz sine wave is sampled at 2 kHz without an anti-aliasing filter. At which frequency fa does it appear in the samples? Give it in Hz.

f = 1.1 kHzfs = 2 kHz
fa = Hz
4.Medium
SD0​D1​D2​D3​D4​D5​D6​D7​PTb​12·Tb​57600 Bd, 8E2

A UART sends bytes at 57600 baud in the format 8E2: 8 data bits, an even parity bit and 2 stop bit(s), plus the start bit. Find the largest number of data bytes per second it can transfer.

baud = 57600 Bd8E2
RB = B/s
5.Hard
1216⋮16 ch∿01tc​ = 5 µstset​ = 0.5 µsfs​ = ?

A 16-channel multiplexer feeds one ADC. Each conversion takes 5 µs, and after every channel switch the input needs 0.5 µs to settle. The channels are scanned in turn without pause. Find the sampling rate fs of each channel, in kHz.

n = 16tc = 5 µstset = 0.5 µs
fs = kHz
6.Hard
SD0​D1​D2​D3​D4​D5​D6​D7​Tb​10·Tb​9600 Bd, 8N1

A 16-bit ADC streams every sample over a UART at 9600 baud, format 8N1 (start bit, 8 data bits, 1 stop bit). Each sample is sent as 2 whole byte(s) and the link is busy all the time. Find the highest signal frequency fmax that can be sampled without aliasing, in Hz.

baud = 9600 BdN = 168N1
fmax = Hz

Answer key

  1. 1. Rb = 500 kbit/s
  2. 2. Tb = 104.2 µs
  3. 3. fa = 900 Hz
  4. 4. RB = 4800 B/s
  5. 5. fs = 11.36 kHz
  6. 6. fmax = 240 Hz

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