Data acquisition & sampling worksheet with answers

Free printable Data acquisition & sampling worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vin​N = 123.3 V2ᴺ − 101 LSB = ?

A 12-bit ADC has an input range of 0 to 3.3 V. Taking 1 LSB = VFSR/2ᴺ, find the size of one LSB in mV.

N = 12VFSR = 3.3 V
1 LSB = mV
2.Easy
f0fs​/2fs​ = ?22 kHz

A sensor signal contains frequencies up to 22 kHz. Find the minimum sampling rate fs,min that captures it without aliasing.

fmax = 22 kHz
fs,min = kHz
3.Medium
Vin​N = 24VFSR​2ᴺ − 101 LSB

Find the ideal signal-to-quantisation-noise ratio SQNR of a 24-bit ADC for a full-scale sine wave.

N = 24
SQNR = dB
4.Medium
tTs​ = 1/fs​f = 17 kHzfs​ = 20 kHz

A 17 kHz sine wave is sampled at 20 kHz without an anti-aliasing filter. At which frequency fa does it appear in the samples? Give it in kHz.

f = 17 kHzfs = 20 kHz
fa = kHz
5.Hard
SD0​D1​D2​D3​D4​D5​D6​D7​Tb​10·Tb​19200 Bd, 8N1

A 24-bit ADC streams every sample over a UART at 19200 baud, format 8N1 (start bit, 8 data bits, 1 stop bit). Each sample is sent as 3 whole byte(s) and the link is busy all the time. Find the highest signal frequency fmax that can be sampled without aliasing, in Hz.

baud = 19200 BdN = 248N1
fmax = Hz
6.Hard
SD0​D1​D2​D3​D4​D5​D6​D7​1/fbaud​4 MHz / (16·D)

A microcontroller with a 4 MHz clock sets its UART baud rate as fclk/(16·D), with D a whole number rounded to the nearest value. The target is 19200 baud. Find the percentage error of the real baud rate (positive when it is too fast).

fclk = 4 MHztarget = 19200 Bd
e = %

Answer key

  1. 1. 1 LSB = 0.8057 mV
  2. 2. fs,min = 44 kHz
  3. 3. SQNR = 146.2 dB
  4. 4. fa = 3 kHz
  5. 5. fmax = 320 Hz
  6. 6. e = 0.1603 %

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