DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−24 VRa​ = 0.5 ΩIa​ = ?M+−E = 0n = 0T

A DC motor with an armature resistance of 0.5 Ω is switched directly onto a 24 V supply. Its normal full-load current is 2 A. Find the armature current Istart at the moment of starting.

V = 24 VRa = 0.5 Ω
Istart = A
2.Easy
+−110 VRa​ = 1.2 ΩIa​ = ?M+−E = 0n = 0T

A DC motor with an armature resistance of 1.2 Ω is switched directly onto a 110 V supply. Its normal full-load current is 6 A. Find the armature current Istart at the moment of starting.

V = 110 VRa = 1.2 Ω
Istart = A
3.Medium
T (N·m)n (rpm)3.75 N·mn0​n = ?

A DC motor (k = 0.75 N·m/A, Ra = 0.8 Ω) runs from 110 V and drives a load torque of 3.75 N·m. Find its speed n in rpm.

V = 110 Vk = 0.75 N·m/ARa = 0.8 ΩT = 3.75 N·m
n = rpm
4.Medium
T (N·m)n (rpm)n0​ = ?

A DC motor with k = 0.8 V·s/rad runs from 240 V. Neglecting all losses at no load, find its no-load speed n0 in rpm.

V = 240 Vk = 0.8 V·s/rad
n0 = rpm
5.Hard
+−240 VRa​ = 0.8 ΩIa​: 25 → 10 AM+−En = ?T

A separately excited DC motor on 240 V (Ra = 0.8 Ω) runs at 1800 rpm with an armature current of 25 A. The load changes and the current becomes 10 A, with the field unchanged. Find the new speed n2.

V = 240 VRa = 0.8 Ωn1 = 1800 rpmIa1 = 25 AIa2 = 10 A
n2 = rpm
6.Hard
+−240 VRs​ = ?Ra​ = 0.8 ΩM+−En = 1500 rpmT = 9 N·m

A DC motor (k = 0.6 V·s/rad, Ra = 0.8 Ω) on a fixed 240 V supply drives a load of 9 N·m. Find the series resistance Rs that slows it down to 1500 rpm.

V = 240 Vk = 0.6 V·s/radRa = 0.8 ΩT = 9 N·mn = 1500 rpm
Rs = Ω

Answer key

  1. 1. Istart = 48 A
  2. 2. Istart = 91.67 A
  3. 3. n = 1350 rpm
  4. 4. n0 = 2865 rpm
  5. 5. n2 = 1898 rpm
  6. 6. Rs = 8.917 Ω

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