DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−240 VRa​ = 1 ΩIa​ = 20 AM+−EωT

A DC motor runs from 240 V with an armature current of 20 A. The armature resistance is 1 Ω. Find the developed (electromagnetic) power Pdev.

V = 240 VIa = 20 ARa = 1 Ω
Pdev = W
2.Easy
+−120 VRa​M+−E = 108 Vn = 1500 rpmT

A DC motor turns at 1500 rpm, and its back-EMF at that speed is 108 V. Find the motor constant k in V·s/rad.

E = 108 Vn = 1500 rpm
k = V·s/rad
3.Medium
T (N·m)n (rpm)25 N·mn0​nFL​

A DC motor (k = 1 V·s/rad, Ra = 0.5 Ω) runs from 110 V. At full load it draws 25 A. Neglecting the no-load current, find its speed regulation SR = (n₀ − nFL)/nFL in percent.

V = 110 Vk = 1 V·s/radRa = 0.5 ΩIFL = 25 A
SR = %
4.Medium
T (N·m)n (rpm)Tst​ = ?n0​

A DC motor with k = 1 N·m/A and Ra = 0.2 Ω is connected to 240 V. Find its stall torque Tstall, the torque at zero speed.

V = 240 Vk = 1 N·m/ARa = 0.2 Ω
Tstall = N·m
5.Hard
+−220 VRa​ = 1 ΩIa​: 25 → 12.5 AM+−En = ?T

A separately excited DC motor on 220 V (Ra = 1 Ω) runs at 1440 rpm with an armature current of 25 A. The load changes and the current becomes 12.5 A, with the field unchanged. Find the new speed n2.

V = 220 VRa = 1 Ωn1 = 1440 rpmIa1 = 25 AIa2 = 12.5 A
n2 = rpm
6.Hard
+−120 VRst​ = ?Ra​ = 0.2 Ω100 AM+−E = 0n = 0T

A 120 V DC motor has an armature resistance of 0.2 Ω. Find the series starting resistance Rst that limits the starting current to 100 A.

V = 120 VRa = 0.2 ΩImax = 100 A
Rst = Ω

Answer key

  1. 1. Pdev = 4400 W
  2. 2. k = 0.6875 V·s/rad
  3. 3. SR = 12.82 %
  4. 4. Tstall = 1200 N·m
  5. 5. n2 = 1532 rpm
  6. 6. Rst = 1 Ω

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