DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−110 VRa​ = 0.5 ΩIa​ = 10 AM+−EωT

A DC motor runs from 110 V with an armature current of 10 A. The armature resistance is 0.5 Ω. Find the developed (electromagnetic) power Pdev.

V = 110 VIa = 10 ARa = 0.5 Ω
Pdev = W
2.Easy
+−48 VRa​M+−E = 43.2 Vn = 1450 rpmT

A DC motor turns at 1450 rpm, and its back-EMF at that speed is 43.2 V. Find the motor constant k in V·s/rad.

E = 43.2 Vn = 1450 rpm
k = V·s/rad
3.Medium
T (N·m)n (rpm)4 N·mn0​nFL​

A DC motor (k = 0.8 V·s/rad, Ra = 2 Ω) runs from 110 V. At full load it draws 5 A. Neglecting the no-load current, find its speed regulation SR = (n₀ − nFL)/nFL in percent.

V = 110 Vk = 0.8 V·s/radRa = 2 ΩIFL = 5 A
SR = %
4.Medium
T (N·m)n (rpm)0.5 N·mn0​nFL​

A DC motor (k = 0.1 V·s/rad, Ra = 0.4 Ω) runs from 24 V. At full load it draws 5 A. Neglecting the no-load current, find its speed regulation SR = (n₀ − nFL)/nFL in percent.

V = 24 Vk = 0.1 V·s/radRa = 0.4 ΩIFL = 5 A
SR = %
5.Hard
+−240 VRs​ = ?Ra​ = 0.25 ΩM+−En = 300 rpmT = 30 N·m

A DC motor (k = 1 V·s/rad, Ra = 0.25 Ω) on a fixed 240 V supply drives a load of 30 N·m. Find the series resistance Rs that slows it down to 300 rpm.

V = 240 Vk = 1 V·s/radRa = 0.25 ΩT = 30 N·mn = 300 rpm
Rs = Ω
6.Hard
+−120 VRa​ = 0.4 ΩIa​: 40 → 10 AM+−En = ?T

A separately excited DC motor on 120 V (Ra = 0.4 Ω) runs at 1000 rpm with an armature current of 40 A. The load changes and the current becomes 10 A, with the field unchanged. Find the new speed n2.

V = 120 VRa = 0.4 Ωn1 = 1000 rpmIa1 = 40 AIa2 = 10 A
n2 = rpm

Answer key

  1. 1. Pdev = 1050 W
  2. 2. k = 0.2845 V·s/rad
  3. 3. SR = 10 %
  4. 4. SR = 9.091 %
  5. 5. Rs = 6.703 Ω
  6. 6. n2 = 1115 rpm

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