DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−24 VRa​ = 0.5 ΩIa​ = ?M+−E = 0n = 0T

A DC motor with an armature resistance of 0.5 Ω is switched directly onto a 24 V supply. Its normal full-load current is 4 A. Find the armature current Istart at the moment of starting.

V = 24 VRa = 0.5 Ω
Istart = A
2.Easy
+−110 VRa​Ia​ = 25 AM+−EωT = ?

A permanent-magnet DC motor has the torque constant k = 1.2 N·m/A. Find the torque T it develops at an armature current of 25 A.

k = 1.2 N·m/AIa = 25 A
T = N·m
3.Medium
+−220 VRa​ = 0.4 ΩIa​ = 50 AM+−EωT

A DC motor draws 50 A from a 220 V supply. Its armature resistance is 0.4 Ω and its rotational (friction, windage and iron) losses are 500 W. Find its efficiency η.

V = 220 VIa = 50 ARa = 0.4 ΩProt = 500 W
η = %
4.Medium
T (N·m)n (rpm)3 N·mn0​nFL​

A DC motor (k = 0.6 V·s/rad, Ra = 1 Ω) runs from 48 V. At full load it draws 5 A. Neglecting the no-load current, find its speed regulation SR = (n₀ − nFL)/nFL in percent.

V = 48 Vk = 0.6 V·s/radRa = 1 ΩIFL = 5 A
SR = %
5.Hard
+−120 VRa​ = 2.5 ΩM+−EωT

A small DC motor has an armature resistance of 2.5 Ω and runs from 120 V. Neglecting rotational losses, find the largest mechanical power Pmax it can develop at any speed.

V = 120 VRa = 2.5 Ω
Pmax = W
6.Hard
+−220 VRa​ = 1 ΩIa​: 12 → 4.8 AM+−En = ?T

A separately excited DC motor on 220 V (Ra = 1 Ω) runs at 1440 rpm with an armature current of 12 A. The load changes and the current becomes 4.8 A, with the field unchanged. Find the new speed n2.

V = 220 VRa = 1 Ωn1 = 1440 rpmIa1 = 12 AIa2 = 4.8 A
n2 = rpm

Answer key

  1. 1. Istart = 48 A
  2. 2. T = 30 N·m
  3. 3. η = 86.36 %
  4. 4. SR = 11.63 %
  5. 5. Pmax = 1440 W
  6. 6. n2 = 1490 rpm

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