DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−240 VRa​ = 1.5 ΩIa​ = ?M+−E = 0n = 0T

A DC motor with an armature resistance of 1.5 Ω is switched directly onto a 240 V supply. Its normal full-load current is 6 A. Find the armature current Istart at the moment of starting.

V = 240 VRa = 1.5 Ω
Istart = A
2.Easy
+−48 VRa​ = 0.4 ΩIa​ = ?M+−E = 46.4 VωT

A DC motor on a 48 V supply has an armature resistance of 0.4 Ω. At its present speed the back-EMF is 46.4 V. Find the armature current Ia.

V = 48 VE = 46.4 VRa = 0.4 Ω
Ia = A
3.Medium
T (N·m)n (rpm)20 N·mn0​nFL​

A DC motor (k = 1 V·s/rad, Ra = 0.5 Ω) runs from 220 V. At full load it draws 20 A. Neglecting the no-load current, find its speed regulation SR = (n₀ − nFL)/nFL in percent.

V = 220 Vk = 1 V·s/radRa = 0.5 ΩIFL = 20 A
SR = %
4.Medium
T (N·m)n (rpm)24 N·mn0​n = ?

A DC motor (k = 1.2 N·m/A, Ra = 1 Ω) runs from 220 V and drives a load torque of 24 N·m. Find its speed n in rpm.

V = 220 Vk = 1.2 N·m/ARa = 1 ΩT = 24 N·m
n = rpm
5.Hard
+−240 VRst​ = ?Ra​ = 1.2 Ω80 AM+−E = 0n = 0T

A 240 V DC motor has an armature resistance of 1.2 Ω. Find the series starting resistance Rst that limits the starting current to 80 A.

V = 240 VRa = 1.2 ΩImax = 80 A
Rst = Ω
6.Hard
+−110 VRa​ = 0.4 ΩIa​: 30 → 18 AM+−En = ?T

A separately excited DC motor on 110 V (Ra = 0.4 Ω) runs at 900 rpm with an armature current of 30 A. The load changes and the current becomes 18 A, with the field unchanged. Find the new speed n2.

V = 110 VRa = 0.4 Ωn1 = 900 rpmIa1 = 30 AIa2 = 18 A
n2 = rpm

Answer key

  1. 1. Istart = 160 A
  2. 2. Ia = 4 A
  3. 3. SR = 4.762 %
  4. 4. n = 1592 rpm
  5. 5. Rst = 1.8 Ω
  6. 6. n2 = 944.1 rpm

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