Let f(x) = 4x5 + x2 + 4x − 8. Find the slope of the graph at x = 1, that is f′(1).
Derivatives worksheet with answers
1.Easy
f(x) = 4x5 + x2 + 4x − 8x = 1
f′(1) =
2.Easy
Let f(x) = 2x4 − x2 + 2x − 2. Find the slope of the graph at x = −1, that is f′(−1).
f(x) = 2x4 − x2 + 2x − 2x = −1
f′(−1) =
3.Medium
Let f(x) = ln(3x2 + 5). Find f′(−2).
f(x) = ln(3x2 + 5)x = −2
f′(−2) =
4.Medium
Let f(x) = (−2x − 3)3. Find f′(−1).
f(x) = (−2x − 3)3x = −1
f′(−1) =
5.Hard
The tangent line to f(x) = x2 − 5x + 4 at x = 1 crosses the y-axis at y = b. Find b.
f(x) = x2 − 5x + 4x = 1
b =
6.Hard
Let f(x) = x3 + 6x2 + 9x − 4. Find the x-coordinate x of the local maximum.
f(x) = x3 + 6x2 + 9x − 4
x =
Answer key
- 1. f′(1) = 26
- 2. f′(−1) = −4
- 3. f′(−2) = −0.7059
- 4. f′(−1) = −6
- 5. b = 3
- 6. x = −3
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