Let f(x) = −2x3 + 4x2 + 3x − 4. Find the slope of the graph at x = −1, that is f′(−1).
Derivatives worksheet with answers
1.Easy
f(x) = −2x3 + 4x2 + 3x − 4x = −1
f′(−1) =
2.Easy
Let f(x) = −4x4 − 5x2 − 8x − 5. Find the slope of the graph at x = 1, that is f′(1).
f(x) = −4x4 − 5x2 − 8x − 5x = 1
f′(1) =
3.Medium
Let f(x) = ln(2x2 + 1). Find f′(2).
f(x) = ln(2x2 + 1)x = 2
f′(2) =
4.Medium
Let f(x) = x2·e2x. Find f′(1.5).
f(x) = x2·e2xx = 1.5
f′(1.5) =
5.Hard
Let f(x) = x3 + 10.5x2 + 36x − 1. Find the x-coordinate x of the local minimum.
f(x) = x3 + 10.5x2 + 36x − 1
x =
6.Hard
Let f(x) = x3 + 4.5x2 + 6x + 4. Find the x-coordinate x of the local maximum.
f(x) = x3 + 4.5x2 + 6x + 4
x =
Answer key
- 1. f′(−1) = −11
- 2. f′(1) = −34
- 3. f′(2) = 0.8889
- 4. f′(1.5) = 150.6
- 5. x = −3
- 6. x = −2
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