Let f(x) = −2x3 + 6x2 − 4x − 8. Find the slope of the graph at x = −1, that is f′(−1).
Derivatives worksheet with answers
1.Easy
f(x) = −2x3 + 6x2 − 4x − 8x = −1
f′(−1) =
2.Easy
Let f(x) = x5 + 3x2 + 4x − 7. Find the slope of the graph at x = 3, that is f′(3).
f(x) = x5 + 3x2 + 4x − 7x = 3
f′(3) =
3.Medium
Let f(x) = x3·e2x. Find f′(1.5).
f(x) = x3·e2xx = 1.5
f′(1.5) =
4.Medium
Let f(x) = (2x + 5)5. Find f′(0).
f(x) = (2x + 5)5x = 0
f′(0) =
5.Hard
Let f(x) = x3 − 12x2 + 36x + 5. Find the x-coordinate x of the local minimum.
f(x) = x3 − 12x2 + 36x + 5
x =
6.Hard
The tangent line to f(x) = −x2 + 2x − 3 at x = 3 crosses the y-axis at y = b. Find b.
f(x) = −x2 + 2x − 3x = 3
b =
Answer key
- 1. f′(−1) = −22
- 2. f′(3) = 427
- 3. f′(1.5) = 271.2
- 4. f′(0) = 6250
- 5. x = 6
- 6. b = 6
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