A mass–spring–damper is described by y″ + 2y′ + 100y = 0. Compare it with y″ + 2ζωny′ + ωn²y = 0 and find the damping ratio ζ.
Differential equations worksheet with answers
1.Easy
y″ + 2y′ + 100y = 0
ζ =
2.Easy
A bacterial culture starts with 500 cells and grows according to dN/dt = k·N with k = 0.28 h⁻¹. How many cells N are there after 5 h?
N0 = 500k = 0.28 h⁻¹t = 5 h
N =
3.Medium
A cup of coffee at 85 °C is left in a room at 20 °C. It follows Newton's law of cooling, dT/dt = −k·(T − Tₐ). With k = 0.07 min⁻¹, find its temperature T after 16 min.
T0 = 85 °CTa = 20 °Ck = 0.07 min⁻¹t = 16 min
T = °C
4.Medium
A forged steel part at 420 °C is left to cool in a workshop at 29 °C. It follows Newton's law of cooling, dT/dt = −k·(T − Tₐ). With k = 0.03 min⁻¹, find its temperature T after 50 min.
T0 = 420 °CTa = 29 °Ck = 0.03 min⁻¹t = 50 min
T = °C
5.Hard
Solve y′ + y = 5e−0.5t with y(0) = 4. Find y(1).
y′ + y = 5e−0.5ty(0) = 4
y(1) =
6.Hard
A system obeys y″ + y′ + 9.25y = 18.5 for t ≥ 0, starting from rest: y(0) = 0, y′(0) = 0. Find the peak value ymax of its step response.
y″ + y′ + 9.25y = 18.5y(0) = 0y′(0) = 0
ymax =
Answer key
- 1. ζ = 0.1
- 2. N = 2028
- 3. T = 41.21 °C
- 4. T = 116.2 °C
- 5. y(1) = 3.858
- 6. ymax = 3.185
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