A mass–spring–damper is described by y″ + 2y′ + 25y = 0. Compare it with y″ + 2ζωny′ + ωn²y = 0 and find the damping ratio ζ.
Differential equations worksheet with answers
1.Easy
y″ + 2y′ + 25y = 0
ζ =
2.Easy
A mass–spring–damper is described by y″ + 4.8y′ + 36y = 0. Compare it with y″ + 2ζωny′ + ωn²y = 0 and find the damping ratio ζ.
y″ + 4.8y′ + 36y = 0
ζ =
3.Medium
Solve y″ + 5y′ + 6y = 0 with y(0) = 5 and y′(0) = 0. Find y(1.5).
y″ + 5y′ + 6y = 0y(0) = 5y′(0) = 0
y(1.5) =
4.Medium
Solve y″ + 2y′ + y = 0 with y(0) = 5 and y′(0) = 0. Find y(1).
y″ + 2y′ + y = 0y(0) = 5y′(0) = 0
y(1) =
5.Hard
A system obeys y″ + y′ + 4.25y = 8.5 for t ≥ 0, starting from rest: y(0) = 0, y′(0) = 0. Find y(0.75); angles in radians.
y″ + y′ + 4.25y = 8.5y(0) = 0y′(0) = 0
y(0.75) =
6.Hard
Solve y″ + 2y′ + 5y = 0 with y(0) = 10 and y′(0) = 0 (released from rest). Find y(0.5); angles in radians.
y″ + 2y′ + 5y = 0y(0) = 10y′(0) = 0
y(0.5) =
Answer key
- 1. ζ = 0.2
- 2. ζ = 0.4
- 3. y(1.5) = 0.6357
- 4. y(1) = 3.679
- 5. y(0.75) = 1.56
- 6. y(0.5) = 5.829
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