A quantity grows according to dy/dt = k·y with k > 0. It is 80 at t = 0 and 208 at t = 2 h. Find the rate constant k in h⁻¹.
Differential equations worksheet with answers
1.Easy
y(0) = 80y(2) = 208
k = h⁻¹
2.Easy
A quantity grows according to dy/dt = k·y with k > 0. It is 250 at t = 0 and 675 at t = 9 h. Find the rate constant k in h⁻¹.
y(0) = 250y(9) = 675
k = h⁻¹
3.Medium
Solve y″ + 3y′ + 2y = 0 with y(0) = 1 and y′(0) = 2. Find y(1.5).
y″ + 3y′ + 2y = 0y(0) = 1y′(0) = 2
y(1.5) =
4.Medium
Solve y″ + 8y′ + 16y = 0 with y(0) = 3 and y′(0) = -2. Find y(1.5).
y″ + 8y′ + 16y = 0y(0) = 3y′(0) = -2
y(1.5) =
5.Hard
Solve the initial value problem y′ + 3y/x = 3x2 for x > 0, with y(1) = 5. Find y(3).
y′ + 3y/x = 3x2y(1) = 5
y(3) =
6.Hard
Solve y′ + 2y = 2e−3t with y(0) = 3. Find y(1).
y′ + 2y = 2e−3ty(0) = 3
y(1) =
Answer key
- 1. k = 0.4778 h⁻¹
- 2. k = 0.1104 h⁻¹
- 3. y(1.5) = 0.7432
- 4. y(1.5) = 0.04462
- 5. y(3) = 13.67
- 6. y(1) = 0.5771
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