A quantity grows according to dy/dt = k·y with k > 0. It is 400 at t = 0 and 520 at t = 4 h. Find the rate constant k in h⁻¹.
Differential equations worksheet with answers
1.Easy
y(0) = 400y(4) = 520
k = h⁻¹
2.Easy
A quantity grows according to dy/dt = k·y with k > 0. It is 400 at t = 0 and 1040 at t = 4 h. Find the rate constant k in h⁻¹.
y(0) = 400y(4) = 1040
k = h⁻¹
3.Medium
Solve y″ + 8y′ + 16y = 0 with y(0) = 5 and y′(0) = -2. Find y(1).
y″ + 8y′ + 16y = 0y(0) = 5y′(0) = -2
y(1) =
4.Medium
Solve y″ + 3y′ + 2y = 0 with y(0) = 3 and y′(0) = -4. Find y(1.5).
y″ + 3y′ + 2y = 0y(0) = 3y′(0) = -4
y(1.5) =
5.Hard
Solve the initial value problem y′ + 3y/x = 3 for x > 0, with y(1) = 3. Find y(3).
y′ + 3y/x = 3y(1) = 3
y(3) =
6.Hard
A system obeys y″ + 2y′ + 17y = 85 for t ≥ 0, starting from rest: y(0) = 0, y′(0) = 0. Find y(0.75); angles in radians.
y″ + 2y′ + 17y = 85y(0) = 0y′(0) = 0
y(0.75) =
Answer key
- 1. k = 0.06559 h⁻¹
- 2. k = 0.2389 h⁻¹
- 3. y(1) = 0.4213
- 4. y(1.5) = 0.496
- 5. y(3) = 2.333
- 6. y(0.75) = 7.255
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