A mass–spring–damper is described by y″ + 8y′ + 25y = 0. Compare it with y″ + 2ζωny′ + ωn²y = 0 and find the damping ratio ζ.
Differential equations worksheet with answers
1.Easy
y″ + 8y′ + 25y = 0
ζ =
2.Easy
A mass–spring–damper is described by y″ + 8.4y′ + 36y = 0. Compare it with y″ + 2ζωny′ + ωn²y = 0 and find the damping ratio ζ.
y″ + 8.4y′ + 36y = 0
ζ =
3.Medium
Solve y″ + 8y′ + 15y = 0 with y(0) = 5 and y′(0) = 6. Find y(2).
y″ + 8y′ + 15y = 0y(0) = 5y′(0) = 6
y(2) =
4.Medium
Solve y″ + 2y′ + y = 0 with y(0) = 1 and y′(0) = 4. Find y(1.5).
y″ + 2y′ + y = 0y(0) = 1y′(0) = 4
y(1.5) =
5.Hard
A system obeys y″ + 2y′ + 5y = 50 for t ≥ 0, starting from rest: y(0) = 0, y′(0) = 0. Find the peak value ymax of its step response.
y″ + 2y′ + 5y = 50y(0) = 0y′(0) = 0
ymax =
6.Hard
Solve y′ + 0.5y = 10e−2t with y(0) = 3. Find y(0.5).
y′ + 0.5y = 10e−2ty(0) = 3
y(0.5) =
Answer key
- 1. ζ = 0.8
- 2. ζ = 0.7
- 3. y(2) = 0.03794
- 4. y(1.5) = 1.897
- 5. ymax = 12.08
- 6. y(0.5) = 5.076
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